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andrew11 [14]
2 years ago
9

31= -(1+p) +4CP+6) Please help solve

Mathematics
2 answers:
Dimas [21]2 years ago
4 0

Answer:

p=4CP - 26

C= p/4P + 13/2P

P= P/4C +13/2C

Step-by-step explanation:

LUCKY_DIMON [66]2 years ago
3 0

Answer:

p=4(p+6)-32

Step-by-step explanation:

31=−1−p+4(P+6)

2 Add 11 to both sides.

31+1=-p+4(P+6)

31+1=−p+4(P+6)

3 Simplify 31+131+1 to 3232.

32=-p+4(P+6)

32=−p+4(P+6)

4 Regroup terms.

32=4(P+6)−p

5 Subtract 4(P+6)4(P+6) from both sides.

32-4(P+6)=-p

32−4(P+6)=−p

6 Multiply both sides by -1−1.

-32+4(P+6)=p

−32+4(P+6)=p

7 Regroup terms.

4(P+6)-32=p

4(P+6)−32=p

8 Switch sides.

p=4(P+6)-32

p=4(P+6)−32

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Nady [450]
2(13) = 26
-3(6) = -18
26 -  18
=8
so the answer is A
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2 years ago
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Answer:

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Step-by-step explanation:

-44÷2=-22

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Kaylis [27]

Answer:

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Step-by-step explanation:

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2 years ago
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Mariana [72]

Answer:

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Step-by-step explanation:

The result can be shown in <u>m</u><u>u</u><u>l</u><u>t</u><u>i</u><u>p</u><u>l</u><u>e</u> forms.

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2 years ago
Helloo! please quick help with this it’s super simple
lorasvet [3.4K]

Answer:

1

Step-by-step explanation:

\bigg(3 {w}^{4}  {z}^{3} m \bigg) ^{0}  \\  =  {3}^{0}  \times {w}^{4 \times 0}  \times  {z}^{3 \times 0}  \times  {m}^{0}  \\ =  {3}^{0}  \times {w}^{0}  \times  {z}^{0}  \times  {m}^{0}  \\  = 1 \times 1 \times 1 \times 1.. ( \because {a}^{0 }  = 1) \\  = 1 \\  \therefore \:  \bigg(3 {w}^{4}  {z}^{3} m \bigg) ^{0}  = 1

6 0
3 years ago
Read 2 more answers
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