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andrew11 [14]
3 years ago
9

31= -(1+p) +4CP+6) Please help solve

Mathematics
2 answers:
Dimas [21]3 years ago
4 0

Answer:

p=4CP - 26

C= p/4P + 13/2P

P= P/4C +13/2C

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago
3 0

Answer:

p=4(p+6)-32

Step-by-step explanation:

31=−1−p+4(P+6)

2 Add 11 to both sides.

31+1=-p+4(P+6)

31+1=−p+4(P+6)

3 Simplify 31+131+1 to 3232.

32=-p+4(P+6)

32=−p+4(P+6)

4 Regroup terms.

32=4(P+6)−p

5 Subtract 4(P+6)4(P+6) from both sides.

32-4(P+6)=-p

32−4(P+6)=−p

6 Multiply both sides by -1−1.

-32+4(P+6)=p

−32+4(P+6)=p

7 Regroup terms.

4(P+6)-32=p

4(P+6)−32=p

8 Switch sides.

p=4(P+6)-32

p=4(P+6)−32

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Hello Friend,here is the solution for your question


<span>so the given function is </span>
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i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
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<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

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As a fraction,
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a = kb

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18 = 3k   ⇒   k = 6

Then when b = 5, we would have

a = 6 × 5 = 30

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