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insens350 [35]
3 years ago
13

(x + 3)^2 - 4x^2 Factorise using the difference of two squares

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

3(x + 1)(3 - x).

Step-by-step explanation:

(x + 3)^2 - 4x^2

Using the identity a^2 - b^2 = (a - b)(a + b), we have

(x + 3 - 2x)(x + 3 + 2x)

= (-x + 3)(3x + 3)

= 3(x + 1)(3 - x)

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Damm [24]
Do you know your trig ratios?
3 0
3 years ago
Plz hurry will mark brainiest
aliya0001 [1]

Answer:

B. 4

Step-by-step explanation:

The sign \geq means greater than or equal to

The sign > just means greater than

4 is a solution for x \geq4, because 4 is equal to 4, but not a solution for x>4, because 4 is not greater than 4

Hope this helps! :)

6 0
3 years ago
–4.5t49.5t = 40<br> Please help
dlinn [17]

Answer:

t= -0.18

Step-by-step explanation:

Isolate t to get the unknown number:

(-4.5t)(49.5t) = 40

      Multiply (-4.5t)(49.5t):

                     (-4.5t)(49.5t) = -222.75t

      Now, write full equation:

          -222.75t = 40

      Isolate t by dividing -222.75 on both sides:

           \frac{-222.75}{-222.75}t=\frac{40}{-222.75}

      Cancel out left hand side:

            t=\frac{40}{-222.75}

      Simplify your answer:

              t=-0.17957351

      Approximate to 2 decimals:

           t=-0.18

     

5 0
3 years ago
F(x)=x^2-7 and h(x)=7x-5, then f(h(2))= ?
ziro4ka [17]
<h3>Answer:    74</h3>

==================================================

Work Shown:

h(x) = 7x-5

h(2) = 7(2)-5

h(2) = 14-5

h(2) = 9

f(h(2)) = f(9)

f(x) = x^2-7

f(9) = 9^2-7

f(9) = 81-7

f(9) = 74

f(h(2)) = 74

-----------

Here's a slightly alternative approach:

f(x) = x^2 - 7

f(h(x)) = ( h(x) )^2 - 7

f(h(x)) = ( 7x-5 )^2 - 7

f(h(2)) = ( 7*2-5 )^2 - 7

f(h(2)) = ( 14-5 )^2 - 7

f(h(2)) = ( 9 )^2 - 7

f(h(2)) = 81 - 7

f(h(2)) = 74

7 0
3 years ago
Pamela is 8 years older than Jiri. The sum of their ages is 62. What is Jiri's age?
Sophie [7]

Answer:

dude how are you supposed to figure this out????

Jiri age is 23

Step-by-step explanation:

5 0
3 years ago
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