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blsea [12.9K]
4 years ago
10

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCL. What volume of 3.00 M HCI

Chemistry
2 answers:
netineya [11]4 years ago
8 0

To solve the question you use the following formula:

concentration (1) × volume (1) = concentration (1) × volume (1)

3 M ×  volume (1)  = 1.8 M × 50 mL

volume (1)  = (1.8 M × 50 mL) / 3 M = 30 mL

Alekssandra [29.7K]4 years ago
5 0

Answer:

30.0 ml

Explanation:

1.8 M means 1.8 moles of HCl in 1 liter (or 1000 ml) of solution.

50 ml of solution has:

1.8 moles/(x moles) = 1000 ml/(50 ml)

x = 1.8 moles/(1000 ml) * 50 ml = 0.09 moles  

3 M means 3 moles of HCl in 1 liter of solution.

0.09 moles are found in:

3 moles/(0.09 moles) = 1000 ml/(x ml)

x = 0.09 moles * 1000 ml/(3 moles) = 30 ml

Then, you have to take a sample of 30 ml of a solution 3 M and add 20 ml of the solvent (probably water) to make 50 ml of solution 1.8 M of HCl.

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Oliver heated tungsten cylinder weighing 60 g in a hot water bath. While that was heating , he added 40.37 g of distilled water
Anuta_ua [19.1K]

Answer:

21.12°C

Explanation:

Q = m×c×∆T

Where;

m= mass

c= specific heat capacity

∆T = change in temperature

Qwater = - (Qtungsten)

Note that; the initial temperature of tungsten = final temperature of water

For Water, m= 40.37g, initial temperature=21.3°C, c= 4.184J/g°C

For tungsten, m= 60g, final temperature=24.9°C, c= 0.132J/g°C

(m×c×∆T)water = - (m×c×∆T)tungsten

40.37 × 4.184 × (T-21.3) = - {60 × 0.132 × (24.9-T)}

168.91 (T-21.3) = - { 7.92 (24.9-T)}

168.91T - 3597.8 = - (197.21 - 7.92T)

168.91T - 3597.8 = - 197.21 + 7.92T

168.91T - 7.92T = - 197.21 + 3597.8

160.99T = 3400.59

T = 3400.59/160.99

T = 21.12°C

Therefore, the initial temperature, in °C of tungsten cylinder is 21.12°C

8 0
3 years ago
You are asked to prepare a solution that is 2% by weight ethanol in water. Note that the molecular weight of ethanol is 46.07 g/
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Answer:

0.4429 m

Explanation:

Given that mass % of the ethanol in water = 2%

This means that 2 g of ethanol present in 100 g of ethanol solution.

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of CH_3CH_2OH = 2 g

Molar mass of CH_3CH_2OH = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{2\ g}{46.07\ g/mol}

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Mass of water = 100 - 2  g = 98 g = 0.098 kg ( 1 g = 0.001 kg )

So, molality is:

m=\frac {0.0434\ moles}{0.098\ kg}

<u>Molality = 0.4429 m</u>

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Answer:

B.bonds are broken and new bonds are formed

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Chose one that best fits the question
kramer

Answer:

Explanation:

The fourth one.

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