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Tanya [424]
3 years ago
13

Calculate the heat in kJ required to convert 2.1 g of water at 52.1°C to steam at 100°C. The specific heat of water is 4.184 J/g

°C and the heat of vaporization of water is 2260 J/g.
Chemistry
1 answer:
kondaur [170]3 years ago
4 0

Answer:

5.167 kJ

Explanation:

We have to divide the heating process into two steps: one for the heating process of liquid water (1) and the other for the phase transition from liquid water to steam at 100°C (2)

1 - heating from 52.1°C to 100°C:

heat(1) = m x Cp x ΔT = 2.1 g x 4.184 J/g°C x (100°C-52.1°C) = 420.9 J

2 - vaporization at 100°C:

heat(2) = m x ΔHv = 2.1 g x 2260 J/g = 4746 J

Finally, we add the heat values of the steps:

heat required = heat(1) + heat(2) = 420.9 J + 4746 J = 5166.9 J

Since 1 kJ= 1000 J, we convert from J to kJ:

5166.9 J x 1 kJ/1000 J = 5.1669 kJ ≅ 5.167 kJ

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How many significant figures are needed in the answer when 1.31m is multiplied by 6.5 m​
dmitriy555 [2]

Answer:

two

Explanation:

The number of significant figures needed in the answer is 2.

This is because when finding the products of two numbers, the result is as accurate as the least number of significant figures of the numbers being multiplied.

Here the numbers being multiplied are;

 1.31m

 6.5m

        1.31m has 3 significant figures

          6.5m has 2 significant figures.

So, the product will have 2 significant figures

6 0
2 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
DaniilM [7]
800 joules because it's twice the amount
7 0
3 years ago
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What is the mass of 0.257 mol of calcium nitrate?
poizon [28]

Answer: 42.14 g

Explanation:      calcium nitrate -  Ca(NO_{3} )_{2}

                   , the molar mass of calcium nitrate = 164 g

<h3>                   formula used = given mass/molar mass= no of moles </h3>

                   mass required =0.257*164

                                               =42.14 g

                     

             

4 0
1 year ago
What is he empirical formula for the compound that is of 1.85 moles of nitrogen and 4.63 miles of oxygen
BartSMP [9]

The empirical formula is N₂O₅.

The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.  

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the <em>molar ratio of N:O</em>.  

I like to summarize the calculations in a table.  

<u>Element</u> <u>Moles</u>  <u>Ratio¹ </u>  <u> ×2²  </u>  <u>Integers</u>³

     N        1.85    1             2             2

     O        4.63    2.503   5.005     5

¹To get the molar ratio, you divide each number of moles by the smallest number (1.85).

²Multiply these values by a number (2) that makes the numbers in the ratio close to integers.

³Round off the number in the ratio to integers (2 and 5).

The empirical formula is N₂O₅.

4 0
3 years ago
4. Write the electronic configuration of first 20 elements in the periodic table.
DIA [1.3K]

Answer:

Name Atomic Number Electron Configuration Period 1 Hydrogen 1 1s1 Helium 2 1s2 Period 2 Lithium 3 1s2 2s1 Beryllium 4 1s2 2s2 Boron 5 1s2 2s22p1 Carbon 6 1s2 2s22p2 Nitrogen 7 1s2 2s22p3 Oxygen 8 1s2 2s22p4 Fluorine 9 1s2 2s22p5 Neon 10 1s2 2s22p6 Period 3 Sodium 11 1s2 2s22p63s1 Magnesium 12 1s2 2s22p63s2 Aluminum 13 

7 0
2 years ago
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