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ioda
3 years ago
10

Marge cut 16 pieces of tape. Each piece is 3/8in long HOW MUCH TAPE DID SHE USE???????? meow :3

Mathematics
2 answers:
Alla [95]3 years ago
3 0
To solve this, all you need to do is multiply 16 by 3/8. When you multiply a whole number by a fraction, make the whole number into a fraction by putting it over 1.

16      3
---- x ----        Multiply the numerators together and then the denominators.
 1       8

(16 x 3) / (1 x 8)

48 / 8                   Then divide.

She used 6 inches of tape.

drek231 [11]3 years ago
3 0

Answer:

6 inches

Explanation:

I hope this helps!!!

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A square has a side that is (x-3) units long. If the area of the square is 126.5625 sq units, what is the value of x?
Kitty [74]

Answer:

14.25 units

Step-by-step explanation:

Area of a square= l*b= (x-3)(x-3)=x^{2}-3x-3x+9=x^{2}-6x+9

x^{2}-6x+9=126.5625

x^{2}-6x-117.5625

Solving the equation using quadratic equation then as attached

x=14.25 units

To prove

x-3=14.25-3= 11.25 units

area=11.25*11.25=126.5625 sq units

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Simplify the following expression.
Aleksandr [31]
The correct answer is option A
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A soccer team wins 65% of its matches, and 15% of its matches end in a draw. If the team is scheduled to play 20 matches, about
Finger [1]
The team plays 20 matches. 

65% of the matches, the teams wins
= 20 * 0.65
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Quinn has $31,700 in a savings
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Answer:

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7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
5 0
2 years ago
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