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Mama L [17]
3 years ago
10

The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea

rest whole number, if necessary. 30 square units 60 square units 102 square units 120 square units
Mathematics
2 answers:
GalinKa [24]3 years ago
6 0

Answer:

60

Step-by-step explanation:

got it right on edge

Gekata [30.6K]3 years ago
5 0

Answer:

Brainleist!!!!

Step-by-step explanation:

First calculate the distance between B and D, A and C. 

We have the distance between B and D will be:  sqrt[(x2-x1)^2+(y2-y1)^2] = 8.5

The distance between A and C will be: 14.14 

We have the area of rhombus: 1/2 * 8.5 * 14.14 = 60 square units. 

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Show me how to write the expression for the calculation 5 times the difference of 29 and 14 minus 11
mr Goodwill [35]

Answer:

5(29-14)-11

Step-by-step explanation:

we know that

The expression "the difference of 29 and 14" is equal to (29-14)

The expression "the difference of 29 and 14 minus 11" is equal to (29-14)-11

The complete expression "5 times the difference of 29 and 14 minus 11" is equal to 5(29-14)-11

3 0
3 years ago
Which polyhedron has more faces than an octahedron but fewer faces than an icosahedron? A. Hexahedron B. Cube C. Tetrahedron D.
DaniilM [7]
Octahedron has 8 faces, icosahedron has 20 faces. Therefore the answer is dodecahedron, it has 12 faces.
8 0
3 years ago
Read 2 more answers
PLZ HELP ME, I AM ONLY IN LITTLE GRADE AND ITS EASY FOR YOU GUYS AND PLZ HELPPPPPPPPPPPP!!!!!!!!!!!
Arisa [49]
Hey there!

To figure out how much money each person has, we need to divide. 

4.44 ÷ 3 = 1.48

So each person has $1.48

Hope this helps you!

Always remember, you are a Work Of Art!
- Nicole :) <3
5 0
3 years ago
What are the solutions to the following system of equations? x + y = 3 y = x2 − 9 (3, 0) and (1, 2) (−3, 0) and (1, 2) (3, 0) an
OLga [1]

The solutions for the given system of equations are:

(3, 0), (-4, 7).

<h3>How to solve the given system of equations:</h3>

Here we have the system:

x + y = 3

y = x² - 9

To solve this, we can replace the second equation into the first one, so we get:

x + (x² - 9) = 3

Now we can solve this quadratic equation for x, we need to solve:

x² + x - 12 = 0.

The solutions are given by Bhaskara's formula:

x = \frac{-1 \pm \sqrt{1^2 - 4*1*(-12)} }{2*1} \\\\x = \frac{-1 \pm 7 }{2}

Then the two solutions are:

x = (-1 + 7)/2 = 3

x = (-1 - 7)/2 = -4

To get the y-values correspondent, we can evaluate the linear equation in these two values:

y = 3 - x.

For x = 3:

y = 3 - 3 = 0

For x = -4:

y = 3 + 4 = 7

Then the two solutions are: (3, 0), (-4, 7).

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

3 0
2 years ago
The equation w+bw+36=0 has a unique solution if b=___ or b=____
vodka [1.7K]

Step-by-step explanation:

Answer is b=5 or b=11

In addtion 1

W=-6

-6+5*-6=-36

In addtion 2

W=-3

-3+11*-3=-36

5 0
2 years ago
Read 2 more answers
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