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antoniya [11.8K]
3 years ago
6

Jason wants to use his earnings from Monday and Tuesday for online movie rentals. movies cost $2.96 each to it how many movies c

an Jason rent show your work. on Monday he sold 11.9 pounds of cans in on Tuesday he sold 10.7 pounds of cans. 1 pound equals .40 cents. SHOW YOUR WORK..
Mathematics
2 answers:
Kamila [148]3 years ago
6 0

Answer:

He can rent 3 movies

Step-by-step explanation:

Consider the provided information.

It is given that Jason wants to use his earnings from Monday and Tuesday for online movie rentals. movies cost $2.96 each to it.

On Monday he sold 11.9 pounds of cans in on Tuesday he sold 10.7 pounds of cans.

Total pounds of cans he sold is:

11.9 + 10.7 = 22.6 pounds

He sold 22.6 pounds of can.

1 pound of can equals 0.40

Thus the total amount is:

22.6 × 0.40 = 9.04

So, total earning of two days is $9.04

The movies cost is $2.96 each.

The total movies Jason can rent is:

Movies=\frac{9.04}{2.96}

Movies=3.05 approximately

Hence, he can rent 3 movies

ozzi3 years ago
5 0
On Monday and Tuesday, Jason sold 22,6 pounds of cans, so he made s=22,5 x 0.40=9 
That means that Jason can rent 9/2.96 ≈3 movies
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Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(c) P(X = −2) = 1/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

(c) P(Y = 2) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

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                  P ( X = -2 ):  P ( X_2 = 1 ) * P ( X_1 = 3 )

                                 :  ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 1 / 9 )

   

                  ( X = -1 ):  { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

                 P ( X = -1 ):  P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

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                 P ( X = 1 ):  P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

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                  P ( X = 2 ):  P ( X_2 = 3 ) * P ( X_1 = 1 )

                                    :  ( 1 / 3 ) * ( 1 / 3 )

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- The distribution Y = X_2,

                          P(Y=0) = 0

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Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

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According to given situation;

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Putting value of x from Eqn 2 in Eqn 1

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Putting y=11 in Eqn 2

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There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

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