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Nataly_w [17]
3 years ago
10

The shampoo you like to use is on sale. But you only get the lower price if you buy 3 bottles. You want to know how much you'll

save.
Write a formula that will help you determine how much you'll save by buying 3 bottles
on sale.
Let's let
s = sale price per bottle
r = regular price per bottle
c = cost savings
Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0
Hi there,

The equation to this is going to be : c = 3r - 3s

If you want to get the lower price down you are going to have to buy 3 shampoo bottles in order to get a lower price. The cost you save is the main difference from a regular price. And the answer is c = 3r - 3s
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3. A magical four-sided die is rolled twice. Let S be the sum of the resultsof the two rolls. We are told that the probability t
Fed [463]

Answer:

P(S=k) = (1/35)k

8/21

Step-by-step explanation:

P(S=k) is proportional to k

P(S=k) = ck

Total probability is 1

k = 2,3.... 8

Sum of all probabilities =

2c + 3c + 4c + 5c + 6c + 7c + 8c = 1

35c = 1

c = 1/35

P(S=k) = (1/35)k, where k = 2,3,...8

P(1&1):

P(S=2) = 2/35

P(2&2):

P(S=4)/3 = (1/3)(4/35) = 4/105

Because for S=4: (1,3) (2,2) (3,1) and all are equally likely

P(3&3):

P(S=6)/3 = (1/3)(6/35) = 2/35

Because for S=6: (2,4) (3,3) (4,2)

P(4&4):

P(S=8) = 8/35

P(getting doubles = 2/35 + 4/105 + 2/35 + 8/35 = 40/105 = 8/21

6 0
4 years ago
Ali's dog weighs 8 times as much as her cat together, the two cats weigh 54 pounds. how much does Ali's dog weigh
horrorfan [7]
Ali's dog weighs 864.
3 0
3 years ago
Read 2 more answers
Solve the following inequality.<br> 2x + 2(x+5) &lt;+4(8 – 20)
Ilia_Sergeevich [38]

Answer:

x <-14.5

Step-by-step explanation:

2x + 2(x+5) <+4(8 – 20)

Distribute

2x+2x+10 < 4 (-12)

4x +10 < -48

Subtract 10 from each side

4x+10-10 <-48-10

4x< -58

Divide each side by 4

4x/4 < -58/4

x <-14.5

3 0
3 years ago
Expand. 4(5x + 3) 4(5x + 3)
Effectus [21]
400x to the power of 2 + 480x + 144
4 0
3 years ago
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Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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