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3 years ago

13

If y^8 = 4 and y^7 = 3/x, what is the value of y in terms of x?

1 answer:

sashaice [31]3 years ago

6 0

<span>y^8 = 4
y^7 = 3/x

y(y^7) = 3/x(y)
y^8 = 3y/x

3y/x = 4
3y = 4x
y = 4x/3

Answer: (A)</span>

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3 years ago

What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

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$f( - 4) = 4( - 4) + 9 = - 7$

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$f( - 2) = 4( - 2) + 9 = 1$

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$f(0) = 4(0) + 9 = 9$

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$f(2) = 4(2) + 9 = 17$

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Thus ;

R = { - 7 , 1 , 9 , 17 }

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The correct answer is (( D )) .

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3 years ago