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Anuta_ua [19.1K]
3 years ago
5

What is the general form of the equation for the given circle centered at O(0, 0)?

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

 

hello :<span>
<span>an equation of the circle Center at the O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is :  x² +y² = 41</span></span>

x² +y² - 41=0

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Answer: $169

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Multiply 18 x 8 to find the cost for 8 months. $18 x 8 = $144.

Now add $25 to $144, which equals $169

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Answer:

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Step-by-step explanation:

Given that,

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3 years ago
I need help. Someone help please. (photo)​
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Answer:

Step-by-step explanation:

In order to solve all of these problems, you have to first create an equation. The typical format for an equation looks like this: y = mx + b

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In order to create an equation, you have to find the slope and y-intercept of the function. You can find the slope using this expression: \frac{y2-y1}{x2-x1} To find the y-intercept, you use a known point and the slope in the equation to solve for b.

Now that we know this, we can solve the problems.

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The equation now looks like this: h = 15w + b

Let's use the point (1, 15) from the table to find b

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