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Anuta_ua [19.1K]
3 years ago
5

What is the general form of the equation for the given circle centered at O(0, 0)?

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

 

hello :<span>
<span>an equation of the circle Center at the O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is :  x² +y² = 41</span></span>

x² +y² - 41=0

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Write a polynomial function of the least degree that has roots of 3 and (4 + i).
polet [3.4K]

Answer:

  • x³ - 11x² + 41x - 51

Step-by-step explanation:

The least number of degree is 3 and the third root should be (4 - i) to make polynomial rational.

<u>The polynomial is:</u>

  • (x - 3)(x - (4 + i))(x - (4 + i)) =
  • (x - 3)(x² -x(4 + i + 4 - i) + (4 + i)(4 - i)) =
  • (x - 3)(x² - 8x + 16 - (-1)) =
  • (x - 3)(x² - 8x + 17) =
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4 0
3 years ago
Divide £72 into the ratio 4 : 5.
algol13

Answer:

£32 : £40

Step-by-step explanation:

sum the parts of the ratio, 4 + 5 = 9 parts

Divide the amount by 9 to find the value of one part of the ratio

£72 ÷ 9 = £8 ← value of 1 part of the ratio, then

4 parts = 4 × £8 = £32

5 parts = 5 × £8 = £40

Then

£72 in the ratio 4 : 5 is £32 : £40

4 0
3 years ago
Y+2=1/3 (x+1) please can you help
miskamm [114]

Equation:

y + 2 = 1/3(x+1)

Assuming you are solving for Y:

y + 2 = 1/3(x) + 1/3(1)

(y + 2) - 2 = (1/3x + 1/3) - 2

y = 1/3x + 1/3 - 2

<u>y = 1/3x - 5/3</u>

7 0
3 years ago
If m = 9 and z = -7 then<br> what is m? x Z2?
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I think it’s 9 x (-7)(2) which equals -126
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