1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sholpan [36]
3 years ago
5

Divide the following polynomial, then place the ans

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

Step-by-step explanation:

You might be interested in
Apex Bank is getting ready to offer special interest rates for their online-only savings accounts. How should they advertise the
Leto [7]
Account with the highest APY
5 0
3 years ago
Read 2 more answers
Solve for x in the equation x^2-14+31=63
Bingel [31]
To solve for a variable, you need to get it (x) by itself.

x² - 14 + 31 = 63   Add 31 to -14
x² + 17 = 63   Subtract 17 from both sides of the equation
x² = 46   Square root both sides
x = \pm \sqrt{46}

Check your work by plugging in \sqrt{46} for x and then - \sqrt{46}.

\sqrt{46}² - 14 + 31 = 63   Square \sqrt{46}
46 - 14 + 31 = 63   Subtract 14 from 46
32 + 31 = 63   Add
63 = 63

- \sqrt{46}² - 14 + 31 = 63   Square - \sqrt{46}
46 - 14  + 31 = 63   Subtract 14 from 46
32 + 31 = 63   Add
63 = 63

So, x is \sqrt{46} and - \sqrt{46} .
3 0
3 years ago
Write the point-slope form of the line that passes through the points (-2, 1) and (0, 1). Identify (x1, y1) as (0, 1)
mel-nik [20]
M = 1 -1 /dx = 0

y = b

y = 1 

the line is horizontal ( has one value for y for any given x)
7 0
3 years ago
Someone please help me! <br> Solve 14x + 2 = 9
Alenkasestr [34]

subtract 2 from 2 and 9

that gives you 14x=7

divide both sides by 14

that gives you x=7/14

which =1/2

so x=1/2

7 0
3 years ago
A set V is given, together with definitions of addition and scalar multiplication. Determine which properties of a vector space
Galina-37 [17]

Answer:

Properties 1,2, 5(a) and 5(c) are satisfied, the rest of the properties arent valid.

Step-by-step explanation:

Note that both sum and scalar multiplication involves in exchanging the order from that main coefficient with the independent term before doing the standard sum/scalar multiplication.

Property 1 and 2 apply because by exchanging the order of 2 coefficients of a polynomial we obtain a polynomial of degree at most 2, and then we can conclude both properties are valid becuase standard sum of 2 polynomials of degree 2 or less or standard scalar multiplication of a polynomial with a real number will give as a result a polynomial of degree 2 or less.

Property 3 does not apply: Suppose that Property 3 is valid, lets call v = ax² +bx +c the neuter of V. Since v is the neuter, then 0 should be fixed by the neuted, therefore 0 = 0+v = (0x² + 0x + 0) + (ax² +bx +c) = cx²+b²+a.

0 is fixed by v only if c = b = a = 0. Thus, v = 0. If 0 is the neuter, then it should fix x², however 0 + x² = (0x²+0x+0) + (x²+0x+0) = 1. This is a contradiction because x² is not 1. We conclude that V doesnt have a neuter vector. This also means that property 4 doesn't apply either. A set without zero cant have additive inverse

Let v = v2x² + v1x + v0, w = w2x² + w1x + w0. We have that

  • v + w = (v0+w0) * x² + (v1*w1) * x + (v2*w2)
  • w + v = (w0+v0) * x² + (w1*v1) * x + (w2*v2)

Since the sum of real numbers is commutative, we conclude that v+w = w+v. Therefore, property 5(a) is valid.

Property 5(b) is not valid: we will introduce a counter example. lets use v = x², w = x²+1, z = 1, then

  • (v+w)+z = (x²+2)+1 = 3x² + 1
  • v + (w+z) = x² + (2x²+1) = x²+3

Since 3x²+1 ≠ x²+3, then the associativity rule doesnt hold.

Property 5(c) does apply. If v = v2x²+v1x+v0 and w = w2x²+w1x+w0, then we have that, for a real number c

  • c*(v+w) = c*( (v0+w0)x² + (v1+w1)x + (v2+w2) ) = c*(v2+w2) x² + c*(v1+w1) x + c(v0+w0)
  • c*v + c*w = (cv0x²+cv1x+cv2)*(cw0x²+cw1x+cw2) = (cv2+cw2)x²+(cv1+cw1)x+(cv0+cw0)

Note that both expressions are equal due to the distributive rule of real numbers. Also, you can notice that his property holds because in both cases we <em>'swap variables twice'. </em>For this same argument neither of properties 5d and 5e apply, because on one term we swap variables just once and on the other term we swap variables twice. I will give an example with the vector x² + x and the scalars 1 and 2.

  • (1+2)*(x²+x) = 3*(x² + x) = 3x + 3
  • 1*(x²+x)+2*(x²+x) = (x+1)+(2x+2)  = 3x²+x (≠ 3x + 3)
  • (1*2)*(x²+x) = 2*(x²+x) = 2x+2
  • 1*(2*(x²+x)) = 1*(2x+2) = 2x²+2x (≠ 2x+2)

Property f doesnt apply due to the swap of variables. for example, if v = x², 1* v = 1*x² = 1 ≠ v.

6 0
3 years ago
Other questions:
  • For the set A={4}, determine n (A)
    15·1 answer
  • Need help! BIG OFFER FOR POINTS!
    6·1 answer
  • Determine whether the rule represents an exponential function. Explain why or why not.
    5·1 answer
  • a recipe calls for 32 fluid ounces of heavy cream.how many 1-pint containers of heavy cream are needed to make the recipe ?
    8·2 answers
  • If a = 4 and b = 2, what is the value of the following expression?
    9·2 answers
  • Peter has 100 dollars. His mom gives him x dollars more. Write an expression to represent the situation.
    5·2 answers
  • Point m is the midpoint of ab¯¯¯¯¯ . am=3x+3, and ab=8x−6. what is the length of am¯¯¯¯¯¯ ?
    9·1 answer
  • 9/d as a algebraic expression
    6·1 answer
  • HELPPPPPP QUICKKKKKHELPPPPPP QUICKKKKK
    13·2 answers
  • The diameter of a basketball rim is 45 centimeters. What is the measurements around the rim. Use 3.14 for π.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!