Is the product of a positive number and a negative number a positive

Mathematics

1 answer:

quester [9]3 years ago

8 0

Answer:

Hey there!

False. The product of a positive number and a negative number is always NEGATIVE.

Let me know if this helps :)

You might be interested in

The bakers at Good-For-You Bakery can make 500 bagels in 4 hours. How many bagels can they bake in 14 hours?

sergey [27]

Answer:

1750

Step-by-step explanation:

7 0

2 years ago

F (x) = –2x+1<br> If<br> f (x) = 11<br> Find the value of x:

a_sh-v [17]

Answer:

Now x is equals to 11

-2(11) + 1 = - 22 + 1 = - 21

The answer is - 21

Thank you and please rate me as brainliest as it will help me to level up

8 0

2 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.