ANSWER
EXPLANATION
The given function is,
This function has a period of
just as the parent function
A sample period of this parent function is
![[ 0 , 2\pi]](https://tex.z-dn.net/?f=%5B%200%20%2C%202%5Cpi%5D)
Which begins at zero.
For the transformed function,
There has been a horizontal shift of
to the left.
The transformed function will have a sample period,
![[ - \frac{\pi}{4} , \frac{7\pi}{4} ]](https://tex.z-dn.net/?f=%5B%20-%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2C%20%5Cfrac%7B7%5Cpi%7D%7B4%7D%20%5D)
Therefore a sample period begins at
Answer:
1/15 of their time is free time.
Step-by-step explanation:
To find the answer to this 2-step problem, we have to add all the fractions up, then find how much of that time is not part of the fraction.
So to add all the fractions, you have the equation:
1/4 + 3/5 + 1/12
The first thing we have to do is to find a common denominator.
4, 5, and 12 are each able to multiply into 60.
So we can make the equation now with a common denominator.
15/60+36/60+5/60=56/60.
We now can simplfy this.
56/60=14/15
Now that we know how long it is to do all the other activities, it tells us that the rest of the time is free time. To find the rest of the time, we have to do:
1-14/15=1/15
So 1/15 of their time is free time.
Quadrilateral that is a parallelogram
Answer : (1,-1)
a line through the points (-1, 1), (0, 2), (1, 3)
To find the point in the graph of inverse function we interchange x and y values
For point (-1 , 1) , the point on inverse function is (1, -1)
For point (0 , 2) , the point on inverse function is (2, 0)
For point (1 , 3) , the point on inverse function is (3, 1)
so (1,-1) will be included in the graph of the inverse of the function
Answer:
2063.9 kg
Step-by-step explanation:
Given,
<u>1 kg = 2.2046 pounds</u>
This can also be written as:
<u>1 pound = 1/2.2046 kg</u>
We have to calculate the value of 4550 pounds in kg up to nearest 10th
Thus,
Solving the above equation, we get:
4550 pounds = 2063.8664 kg
Rounding the above result to nearest tenth as:
<u>4550 pounds = 2063.9 kg</u>
