If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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You know that e= mc^2. In order to find the Value of mc, you have to take squareroot on both sides. So,
squareroot of e= mc
The length would be 10 inches.
to find perimeter, you add length+length+width+width.
since both widths and both lengths have to be the same, u add the width 2 times or 7+7=14.
next u subtract 14 from 34 or 34-14=20.
since u still have 2 lengths that are equal, u divide 20 by 2 or 20/2=10
hope this helps! :)
Answer:
-8100
Step-by-step explanation:
(2/5)^-2(-3)^4
Given data
and second term
The first term= (2/5)^-2 and
Second term=(-3)^4
Simplify the first term
(2/5)^-2= 2^-2/ 5^-2= 1/2^2 * 1/5^2
=1/4/ 1/25
=1/4*25/1
=100
Simplify the second term
=(-3)^4
= -81
Hence, 100*81
=-8100
The scientific notation of the given, 35,000,000 is 3.5 x 10^7. The order of magnitude of a scientific notation is the exponent of its multiplier, 10. From the derived scientific notation above, the exponent of 10 is 7. Thus, the answer is letter D.
