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3 years ago

I need help on this question plz

Mathematics

2 answers:

vagabundo [1.1K]3 years ago

4 0

The last one should be the answer

Alinara [238K]3 years ago

3 0

the 3rd one down, because all of the points is on/near the line. The line is in the middle of the dots.

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Tina and Maryann each play tennis. Maryann has won 5 more games than Tina. Is it possible for Tina to have won 12 games if the s

Jet001 [13]

Answer:

Yes; Tina could have won 12 games because 2x + 5 = 29.

Step-by-step explanation:

Let

x ----> the number of games that Tina has won

y ---> the number of games that Maryann has won

we know that

$y=x+5$ -----> equation A

$x+y=29$ ----> equation B

substitute equation A in equation B and solve for x

$x+x+5=29$

$2x+5=29$

$2x=29-5$

$2x=24$

$x=12$

The number of games that Tina has won is 12

6 0

3 years ago

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4. Combine Like terms: -7(2 + 3x) + (-3x)(-5) + 9*<br> -7x + 5<br> 0 -7X-5<br> O 7x-5<br> O 7x + 5

Dima020 [189]

Answer:

-69x-9

Step-by-step explanation:

7 0

3 years ago

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Four times the sum n plus 10 is 34 what is the value of n?

vazorg [7]

Answer:

4(10+n)=34

40+4n=34

4n=-6

n=-6/4=-3/2

Step-by-step explanation:

5 0

3 years ago

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Which is the factored form of 3y − 18?

Lesechka [4]

3y-18
Pull out 3 (common factor):
3(y-6)

A) 3(y-6) is the correct answer

6 0

4 years ago

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The number of different species of plants in some gardens is recorded.

PolarNik [594]

(a) The mean of the number of different species of plants in some gardens is 4.5 .

(b) The standard deviation of the number of different species of plants in some gardens is 2.12 (Approximately)

It is given in the question that the number of different species recorded are:-

1 2 3 4 4 5 5 6 7 8

We have to find the mean and standard deviation of the given data of the number of plants of different species.

(a) We know that, the formula for mean is :-

Sum of all the observations/ Total number of observations

Hence,

Mean = $\frac{1+2+3+4+4+5+5+6+7+8}{10} =\frac{45}{10}=4.5$

(b) Standard deviation = $\sqrt{\frac{Sum(X-m)^{2} }{N} }$

Where,

X = each value

m = mean

N = number of values

Hence,

$Sum(X-m)^{2} =(1-4.5)^{2}+(2-4.5)^{2}+ (3-4.5)^{2}+ (4-4.5)^{2}+ (4-4.5)^{2}+ (5-5.5)^{2}+ (5-5.5)^{2}+ (6-5.5)^{2}+ (7-5.5)^{2}+ (8-5.5)^{2}\\ \\ Sum(X-m)^{2}=(-3.5)^{2} +(-2.5)^{2}+ (-1.5)^{2}+ (-0.5)^{2}+ (-0.5)^{2}+ (0.5)^{2}+ (0.5)^{2}+ (1.5)^{2}+ (2.5)^{2}+ (3.5)^{2} \\\\$

$Sum(X-m)^2=12.25+6.25+2.25+0.25+0.25+0.25+0.25+2.25+6.25+12.25\\\\=42.5$

Standard deviation = ${\sqrt{\frac{{42.25}}{10} }} =\frac{6.7}{\sqrt{10} }=\frac{6.7}{3.16}=2.12$ (approximately).

To learn more about mean, here:-

brainly.com/question/13451489

#SPJ4

4 0

1 year ago