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lianna [129]
3 years ago
15

I need help on this question plz

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
4 0

The last one should be the answer

Alinara [238K]3 years ago
3 0

the 3rd one down, because all of the points is on/near the line. The line is in the middle of the dots.

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Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
Help pls <br> Show workings
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- the type of pair is vertical angle.

- to find x:

-- vertical angles are equal.

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10 = x - 1

x = 11

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PLEASE HELP WORTH 14 POINTS!
Liono4ka [1.6K]

Answer:

180°

cuz when a line (I forgot the name) and radius meet at the circumference they from an angle of 90°

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Due to inflationary tendency in the market, the prices of goods have increased. Debra now needs more money to buy the same amoun
Kobotan [32]
I belive it is the second i'm taking the test
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Theos mom bought an eight pack of juice boxes at the store for $4. Find the unit rate for the juice boxes.PLZ HELP ME
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I believe that you need to divide 4 by 8 to get $0.50 per juice box.
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