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3 years ago

2) translation: 3 units down

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

x-3

Step-by-step explanation:

it going down 3 times

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Factor completely 2n + 13n + 15

yKpoI14uk [10]

Hey there!

“Factor completely 2n + 13n + 15”

2n + 13n + 15

COMBINE your LIKE TERMS

(2n + 13n) + (15)

2n + 13n = 15n

15 = 15

Answer: 15n + 15

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

4 0

2 years ago

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Please help i will mark branliest

AfilCa [17]

Answer:

ihnc

Step-by-step explanation:

ihnc

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3 years ago

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Oksana_A [137]

Answer:

x=(-1/10) is the answer of given algebra

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3 years ago

Please help, I will mark you brainiest, thank you’

stich3 [128]

Answer:

Step-by-step explanation:

6 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

3 years ago