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Leno4ka [110]
2 years ago
9

In your own words make a conjecture about the relation

Mathematics
1 answer:
damaskus [11]2 years ago
3 0

Step-by-step explanation:

The congruent angles of the isocels triangle's opposite sides's are congruent.

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What is the unit rate of the proprrional relationship represented by the equation y=3x
NeX [460]

The unit rate of the proportional relationship y = 3x is 3

<h3>How to determine the unit rate?</h3>

The proportional relationship is given as:

y = 3x

Divide both sides by x

y/x = 3

For a proportional relationship y/x = k;

The unit rate is 3

This means that the unit rate of the proportional relationship y = 3x is 3

Read more about proportional relationship at

brainly.com/question/12242745

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6 0
2 years ago
Seven times the difference of some number and 1 gives the quotient of 70 and 10, find the number
Agata [3.3K]
7(x-1)=70/10
7x-7=7
7x=14
x = 2

The number is 2.
6 0
3 years ago
Y=x^2-5x+11<br> Find vertex form
Marat540 [252]

Answer:

42

Step-by-step explanation:

The answer to life the universe and everything is 42

8 0
3 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
1 year ago
rectangular piece of paper 4 cm wide length twice its width measuring 3 cm by 7 cm how many sq cm will be visible on top?
aalyn [17]
22 square centimeters
8 0
3 years ago
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