Answer:
8926 bacteria
Step-by-step explanation:
We have been given that the population of a bacteria in an experiment has been increasing by 80% each day. There were 25 bacteria at the beginning of the experiment. We are asked to find the number of bacteria in 10 days.
We will use exponential growth formula to solve our given problem.
, where,
y = Final amount
a = Initial amount,
r = Growth rate in decimal form,
x = Time.
Upon substituting our given values in above formula, we will get:
To find number of bacteria in 10 days, we will substitute in our formula as:
Therefore, there will be approximately 8926 bacteria in 10 days.
Answer:
d)
Step-by-step explanation:
i¹= i
i²= -1
i³= -i
i⁴= 1
i¹²⁴= i^(124 +0)
i^124 . i^0
i^(4×31) . i^0 = 1³¹. i^0
1.i^0= i^0
= 1
a) i^179= i^(176+3)
i^176 . i³ = i^(4×44) . i³
1⁴⁴. i³ = 1. i³
= -i
b) i^582 = i^(580 + 2)
i^580 . i²= i^(4×145) . i²
1^145 . i²= 1.i²
= -1
c) i^165= i^(164+1)
i^164 . i¹ = i^(4×41) . i¹
1⁴¹ . i¹ = 1.i
= i
d) i^740= i^(740+0)
i^740 . i^0 = i^(4×185) . i^0
1^185 . i^0 = 1. i^0
= 1
i¹²⁴= i^740 = 1
For anyone here who comes from edge.
Consider the reduction of the complex figure with a scale factor of 1
/7
. What is the area of the reduced figure?
The answer is A ; 25 mm2. I got it right on edge
The two in the hundredths place is ten times less than the two in the tenths place.
Answer:
16.7
Step-by-step explanation:
48(-1) + 32.7 - 32(-1)
-48+32.7+32