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KengaRu [80]
4 years ago
14

Someone Help me please

Mathematics
2 answers:
Katarina [22]4 years ago
7 0

Answer:

-1/2

Step-by-step explanation:

the number in front of the X when the equation looks like that is always the slope and the number that is added or subtracted after the x is the Y-intercept(where the line crosses through the Yaxis)

OLEGan [10]4 years ago
3 0

Answer:

-1/2

Step-by-step explanation:

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we know that

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so

In the right triangle ZWY

tan\ ZWY=\frac{ZY}{YW}=\frac{5}{6}

In the right triangle XWY

tan\ WXY=\frac{WY}{XY}=\frac{6}{a}

\frac{6}{a} =\frac{5}{6} \\ \\5*a=6*6 \\ \\a=\frac{36}{5}=7.2\ units

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3 years ago
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The equation is 2.25x2.50.
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4 years ago
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A random sample is selected from a population with mean = 100 and standard deviation = 10. Determine the mean and standard devia
jenyasd209 [6]

The mean and standard deviation of the x sampling distribution for each of the following sample sizes will be N(100,10/\sqrt{41} ), N(100,10/\sqrt{130} ).

<h3>What is the distribution of the sample mean for large samples?</h3>

Suppose X has a distribution with mean \mu and standard deviation \sigma,then,

the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with a mean equal to the mean of X, and a standard deviation equal to \sigma/\sqrt{n}

Symbolically, we write it as:

X \sim N(\mu, \sigma) \implies \overline{X} \sim N(\mu,\sigma/\sqrt{n} )

A random sample is selected from a population with a mean = of 100 and a standard deviation = of 10.

The mean and standard deviation of the x sampling distribution for each of the following sample sizes.

If N=41

X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{41} )

If N=130

X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{130} )

Learn more about standard normal distribution here:

brainly.com/question/10984889

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3 years ago
Graph the system of linear inequalities <br><br> y&gt;x-3<br> y&lt;-x+2
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Answer:

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Answer:

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