Using Pythagorean theorem, we can justify our answer.
if c^2 = a^2 + b^2 then triangle is right one,
if c^2 > a^2 + b^2 then triangle is obtuse and
if c^2 < a^2 + b^2 then triangle is acute triangle.
Here a=8, b=11 and c=16
Put these values in the equation
16^2 = 8 ^2 + 11^2
256 = 64 +121
256> 185
So here c^2 > a^2 + b^2 Which means triangle is obtuse triangle.
Answer: Obtuse Triangle
To find if one is a function, you must see if the pattern is the same.
Domains (x) can not have two values
I forget what the y value is called, but there can be the same y- value for multiple x - values
A. is not a function, because its ordered pairs are all over the place, and the value 4 in the x - value has two values assigned - 0 and 3, which makes it invalid.
B. may be a linear function. Its ordered pairs aren't jumping all over the place.
Both the x and y go up one for one, so the function could be y = x + 3
C. isn't because the x - value 2 has two values. Again, that makes this invalid.
D. is invalid because there is two x - values for 2.
Therefore, the answer is B.
Answer:
9 :)
Step-by-step explanation:
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
5(n) - 2 = 3
3 · 9(m) =27
1. is 27
3^2(s)= 9 · 5(t) = 45 · 2(r) = 90
2. is 90
