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Akimi4 [234]
3 years ago
9

Solve the system using an equivalent system

Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0
Add y to both sides in 1st equation
-2x=y
sub -2x for y in2nd equation
3x-(-2x)=10
3x+2x=10
5x=10
divide 5
x=2

sub back
-2x=y
-2(2)=y
-4=y

(x,y)
(2,-4)
C is ans
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Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit (in dollars) realized from renting out x apar
marishachu [46]

Answer:

To maximize the monthly rental profit, 90 units should be rented out.

The maximum monthly profit realizable is $38,200.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a<0, the vertex is a maximum point, that is, the maximum value happens at x_{v}, and it's value is y_{v}.

In this question:

Quadratic equation with a = -12, b = 2160, c = -59000

To maximize the monthly rental profit, how many units should be rented out?

This is the x-value of the vertex, so:

x_{v} = -\frac{b}{2a} = -\frac{2160}{2(-12)} = \frac{2160}{24} = 90

To maximize the monthly rental profit, 90 units should be rented out.

What is the maximum monthly profit realizable?

This is p(90). So

p(90) = -12(90)^2 + 2160(90) - 59000 = 38200

The maximum monthly profit realizable is $38,200.

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3 years ago
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