What is the y in the equation? 15-y-3y=17

8x – 10 = 3x – 10 + 7x

stira [4]

Answer:

x= 0

Step-by-step explanation:

Let's first simplify the equation to make the PEMDAS process easier.

8x-10=3x-10+7x

8x-10=10x-10

Now lets start the subtracting and dividing process.

8x=10x

0=2x

0=x

6 0

3 years ago

Plz help me. im not as smart as I seem. 7th grade math. extra points!

Strike441 [17]

Okay what’s the question?

7 0

2 years ago

Jackie wants to burn 2000 calories in one week she can burn 250 calories per hour doing aerobics. How many hours should Jackie d

Crank

Answer:

8 hours

Step-by-step explanation:

If Jackie wants to burn 2000 calories in one week but only burns 250 calories per hour

then, to solve how many hours you have to divide

2000/250= 8

therefor Jackie has to do aerobics for 8 hours that week to burn 2000 calories

8 0

3 years ago

What is the first error he made in computing the standard deviation?

artcher [175]

B.yuri divided by n instead of n-1

7 0

2 years ago

Read 2 more answers

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$