Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
I hope this will help u <span>It looks like 12 is the smallest number that can be divided by both 3 and 4, so 12 is our LCD. Since 12 is the LCD, it will be the new denominator for our fractions. Now we'll change the </span>numerators<span> of the fractions, just like we changed the denominators. First, let's look at the fraction on the left: 1/4.</span>
1. The function of this graph is f(x) = 0.5x + -2
Plug (-2) into the x variables so it looks like:
f(-2) = 0.5 (-2) + -2
Then solve.
Answer: f(-2) = -3
**I'm not as sure about this one, so I might be wrong
2.
For #8, the y-intercept is 4 (you're right) and it represents the initial distance before she started hiking (D)
I tried to figure #9 out, but I couldn't find the answer. I came across a website that might help though: https://sciencing.com/determine-practical-domain-range-10052000.html
**I can't see #s 6 or 7
We know that the area is 20.
Since 20 is a small number: lets list out possible combinations of lengths and widths.
1 * 20
2 * 10
4 * 5
L = 7 + 3w
lets see which on makes sense.
L = 7 + 3w
20 = w7 + 3w^2
3w^2 + 7w -20 = 0
(3w - 10)(w - 2)
w can equal 10/3 or 2.
So the dimensions: are Width = 2 Length = 10
