The product of addition of bromine to (R)-3-buten-2-ol will bea. a 50:50 mixture of enantiomers.b. a mixture of enantiomers form
ed in unequal amounts.c. a 50:50 mixture of diastereomers.d. a mixture of diastereomers formed in unequal amounts.e. optically inactive.
1 answer:
Answer:
Option D is the answer
D. a mixture of diastereomers formed in unequal amounts.
Explanation:
Chiral intermediates give chiral products
- form unequal mixtures of diastereomers
- transition states are now diastereotopic
• Optically active reactants leads to optically active products.
find attached a diagram of the reaction.
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<h2>70.27 moles</h2>Explanation:
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