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iogann1982 [59]
3 years ago
8

Complete the table by classifying each property as either a physical or chemical property

Chemistry
1 answer:
Advocard [28]3 years ago
8 0
Where is the table? I dont know what to classify 
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How do i find the mass of oxygen in 250 grams of sulfuric acid?
Mashutka [201]

<span> <span> 250g H2SO4 x 1moleH2SO4/ 98g mole H2SO4 x 4moles Oxygen/1moleH2SO4 x 1moleOxgen/16g Oxygen
= 163.27g Oxygen

my figures aren't exact....so it's 160g </span>

</span>
6 0
3 years ago
If water and oil are combine If water and oil are combined in a container, the resulting liquid is a(n) A. solution. B. mixture.
mart [117]
B. Mixture is the answer
8 0
3 years ago
A galvanic cell whose cell reaction is 2Fe3+(aq) + Zn(s) → 2Fe2+(aq) + Zn2+(aq) has a cell potential of 0.72V. What is the maxim
sesenic [268]

Answer:

138.96kJ is the maximum electrical work

Explanation:

The maximum electrical work that can be obtained from a cell is obtained from the equation:

W = -nFE

<em>Where W is work in Joules,</em>

<em>n are moles of electrons = 2mol e- because half-reaction of Zn is:</em>

Zn(s) → Zn²⁺(aq) + 2e⁻

F is faraday constant = 96500Coulombs/mol

E is cell potential = 0.72V

Replacing:

W = -2mol*96500Coulombs/mol*0.72V

W = - 138960J =

<h3>138.96kJ is the maximum electrical work</h3>

<em />

5 0
2 years ago
How many grams of Br are in 335g of CaBr2
ASHA 777 [7]
The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
7 0
3 years ago
....Which is the best classification for West Nile virus?
Luba_88 [7]

Answer:

The answer is F

Explanation: Only because Henrieta wasn't the sister that got kicked out

5 0
2 years ago
Read 2 more answers
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