In order to solve this, you have to plug in all of the costs of the gifts and add them, which in all equals $36. since jim only has 1/4 of the money he needs to buy the gifts, you need to divide 36 by 4. this gives you 9, so now you know he has 9 dollars.
and to find out how much more money he needs, you can subtract 9 from 36 which represents a fourth of the required money. the answer is 27, that's how much jim needs in order to buy his gifts.
<span>3(7 + 4)2 − 14 ÷ 7
First do the parenthesis
7 + 4 = 11
so the question looks like: 3(11)2 - 14/7
Then multiply 3, 11, and 2 together
3 x 11 x 2 = 66
66 - 14/7
14/7 equals to 2
66 - 2
Then just simplify
66 - 2 = 64
64 is your answer
hope this helps</span>
To solve this simply divide 4 by 3 and use the long division and do the same for 11 and 9, then compare the values.
Answer:
c. (x^2+1)(x^2+a)-a = x^2(x^2+a+1)
Step-by-step explanation:
You can use FOIL or the distributive property to expand the product of binomials, Then collect terms and factor out the common factor.
(x^2+1)(x^2+a)-a
= x^2(x^2 +a) +1(x^2 +a) -a
= x^4 +ax^2 +x^2 +a -a
= x^4 +ax^2 +x^2
= x^2(x^2 +a +1) . . . . . matches choice C
Answer:
The figure is NOT unique.
Imagine the following quadrilaterals:
Rectangle
Square
We know that:
Both quadrilaterals have at least two right angles.
However, they are not unique because they depend on the lengths of their sides.
Step-by-step explanation:
To construct a quadrilateral uniquely, five measurements are required. A quadrilateral can be constructed uniquely if the lengths of its four sides and a diagonal are given or if the lengths of its three sides and two diagonals are given.
Just given two angles we cannot construct a unique quadrilateral. There may be an infinite number of quadrilaterals having atleast two right angles
Examples:
All squares with varying sides
All trapezoids with two right angles
All rectangles with different dimensions
and so on.
Answer is
No.
