Answer: A. 
B. A'(5) = 1.76 cm/s
Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.
A. Area of a circle is given by
So to find the rate of the area:
Using 
Then
![\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%3D2.%5Cpi.r.%5B%5Cfrac%7B726%7D%7B%28t%2B11%29%5E%7B3%7D%7D%5D)
![\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%3D2.%5Cpi.%5B3-%5Cfrac%7B363%7D%7B%28t%2B11%29%5E%7B2%7D%7D%5D.%5Cfrac%7B726%7D%7B%28t%2B11%29%5E%7B3%7D%7D)
Multipying and simplifying:
The rate at which the area is increasing is given by expression 
.
B. At t = 5, rate is:
At 5 seconds, the area is expanded at a rate of 1.76 cm/s.
Answer:
the ansqer is g(x) = 4^x-4 + 2
Answer:
So,
if C = 2πR
you take 2π you get 6.28
so C=6.28 x r
the radius is 11.5 so
6.28 x 11.5 = 72.2566
the circumference is 72.2566
Step-by-step explanation:
Answer:
We have been given that a car can travel 476 miles on 14 gallons of gas and we are asked to write an equation relating the distance d to the number of gallons g.
We can set an equation as distance traveled is directly proportional to number of gallons used in travelling that distance.
Now we will find out K(number of miles traveled in one gallon of gas) by substituting our given values in this equation.
Therefore, we can see that car travels 34 miles in one gallon of gas.
Now we can use this information to find out how many gallons of gas does this car need to travel 578 miles.
Let us divide number of miles to be traveled by number of miles traveled in one gallon of gas to find out number of gallons of gas needed.
Therefore, car need 17 gallons of gas to travel 578 miles.
Step-by-step explanation:
Answer:
Theoretical probability is what that you expect to happen to you while experimental is what actually happen when you try it out.
