2 years ago

Who wants to be my friend? :)

Mathematics

1 answer:

olga_2 [115]2 years ago

7 0

Answer:

I want to be your best friend

You might be interested in

Find the product. (-5a2)3 · a5

lesya692 [45]

Answer:

$-125a^{11}$

Step-by-step explanation:

The expression that we have in this problem is

$(-5a^2)^3\cdot a^5$

First of all, we proceed by evaluating the power of the term in the brackets. We apply the rule:

$(a^m)^n=a^{m\cdot n}$

$(a^2)^3=a^6$

Moreover, we have

$(-5)^3=-125$

Therefore,

$(-5a^2)^3=-125 a^6$

So now the expression is

$-125a^6 \cdot a^5$

Now we apply the following rule:

$a^m \cdot a^n = a^{m+n}$

So we have

$a^6\cdot a^5 = a^{6+5}=a^{11}$

Therefore, our expression becomes:

$-125a^6\cdot a^5=-125a^{11}$

3 0

3 years ago

tại teamart,1 ly trà sữa có giá a đồng và 1 ly kem có giá là b đồng.Hãy viết biểu thức đại số biểu thị số tiền bạn Cúc mua 3 ly

Lesechka [4]

Answer:

3 a + 4 b

Step-by-step explanation:

Biểu thức đại số biểu thị bạn Cúc mua 3 ly trà sữa và 4 ly kem là:

3 a + 4 b

8 0

3 years ago

Brainly for correct -- step by step answer <3

Arturiano [62]

Answer:

can you take a better pic so i can help

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Debra borrowed $8000 at a rate of 18% compounded semiannually. Assuming she makes no payment, how much will she owe after 9 year

Marina CMI [18]

Answer:

She owe $37736.96 after 9 years .

Step-by-step explanation:

Debra borrowed $8000 at a rate of 18% compounded semiannually

We are supposed to find how much will she owe after 9 years

Principal = 8000

Rate of interest = 18% =0.18

No. of compounds per year = 2

Time = 9 years

Formula : $A= P(1+\frac{r}{n})^{nt}$

Substitute the values in the formula :

$A= 8000(1+\frac{0.18}{2})^{2 \times 9}$

A= 37736.96

Hence She owe $37736.96 after 9 years .

5 0

3 years ago

What is the answer to this please?

sergij07 [2.7K]

The answer of the rotational symmetry is B, (6)

4 0

3 years ago