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3 years ago

PLEASE HELP SOON!!!!!;((((

Mathematics

1 answer:

Kryger [21]3 years ago

3 0

Ok so easy peasy
remember exponential laws

dividing
$\frac{x^m}{x^n}=x^{m-n}$
also
(ab)/(cd)=(a/c)(b/d)

also
$x^{-m}= \frac{1}{x^m}$
so
$\frac{pq^7r^0}{pq^7r} =( \frac{p^1}{p^1} )( \frac{q^7}{q^7} )( \frac{r^0}{r^1} )$ =(1)(1) $( \frac{1}{r} )$ = $\frac{1}{r}$ = $r^{-1}$

answer is $r^{-1}$

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I think your question missed key information, allow me to add in and hope it will fit the orginal one.

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