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SSSSS [86.1K]
3 years ago
12

PLEASE HELP SOON!!!!!;((((

Mathematics
1 answer:
Kryger [21]3 years ago
3 0
Ok so easy peasy
remember exponential laws

dividing
\frac{x^m}{x^n}=x^{m-n}
also
(ab)/(cd)=(a/c)(b/d)

also
x^{-m}= \frac{1}{x^m}
so
\frac{pq^7r^0}{pq^7r} =( \frac{p^1}{p^1} )( \frac{q^7}{q^7} )( \frac{r^0}{r^1} )=(1)(1)( \frac{1}{r} )=<span>\frac{1}{r}=</span>r^{-1}
<span>
answer is </span>r^{-1}<span>

</span>

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