Question

PLEASE HELP SOON!!!!!;((((

Answer 1

Ok so easy peasy
remember exponential laws

dividing
$\frac{x^m}{x^n}=x^{m-n}$
also
(ab)/(cd)=(a/c)(b/d)

also
$x^{-m}= \frac{1}{x^m}$
so
$\frac{pq^7r^0}{pq^7r} =( \frac{p^1}{p^1} )( \frac{q^7}{q^7} )( \frac{r^0}{r^1} )$=(1)(1)$( \frac{1}{r} )$=$\frac{1}{r}$=$r^{-1}$

answer is $r^{-1}$