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professor190 [17]
3 years ago
13

A teacher is evaluating how students in her first class did on an assessment versus her last class. The box plots show the resul

ts from her math test given to each class. With this data, what is the most reasonable answer to the question: Does the time a student learns math matter for their score?

Mathematics
2 answers:
MrMuchimi3 years ago
4 0

Answer:

The time a student learns mathematics is important for their score

Step-by-step explanation:

Observe the boxes diagrams. Where the horizontal axis represents the score obtained by the students in the test.

The vertical lines that divide the boxes in two represent the value of the median.

The median is the value that divides 50% of the data.

For the class of the morning the value of the median is 50 points, with a maximum value of 80 and a minimum value of 10.

For the afternoon class, the median value is 65 points with a minimum value of 30 and a maximum value of 100.

This indicates that in general, the highest number of high scores were obtained in the afternoon class.

Therefore it can be said that the time a student learns mathematics is important for their  score

deff fn [24]3 years ago
3 0

Answer Sorry if this is too late but the answer is yes because the median test score of the afternoon class is 15 points above the morning class other wise the first option

Step-by-step explanation:

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Please help........................
VashaNatasha [74]

Answer:

<h2>m∠ABD = 20°</h2>

Step-by-step explanation:

If m∠ABC = 40° and BD is the bisector of ∠ABC, then

(1) m∠ABD = m∠DBC

(2) m∠ABC = m∠ABD + m∠DBC

From (1) and (2) we have:

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Therefore

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3 0
3 years ago
The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP​
Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d }    = 30

       5(2a  + 4d )d           = 60

       10a    + 20d             = 60

reduce to lowest term to easy calculation by dividing through by 10

                      a + 2d       = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉  = ⁹/₂(2a + 8d )   = 69

        9(2a  + 8d )    = 30 + 69

            18a + 72d   = 99 x 2

            18a + 72d   = 198

divide through by 18 to reduce to lowest time

                a  + 4d    = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

                 a + 2d = 6

                 a + 4d = 11

                     -2d  = -5

                          d = ⁵/₂.

Now substitute  for d to get a

               a  + 2(⁵/₂) = 6

                a + 5       = 6

                           a   = 6 - 5

                            a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0
2 years ago
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