33/2 =16.5
round down: 16 numbers at most are less than 22
Answer:
11 inches
Step-by-step explanation:
A rectangle's perimeter can be found using:
p=2l+2w
We know that the perimeter, p, is 58, and the length/height is 18. Therefore, we can substitute those values in
58=2(18)+2w
Multiply 2 and 18
58=36+2w
Since we want to find the width, we need to get w by itself. First, subtract 26 from both sides
58-36=36-36+2w
22=2w
Since w is being multiplied by 2, divide both sides by 2. This will cancel out the 2, and leave w by itself.
22/2=2w/2
11=w
So, the width is 11 inches
Answer: The required values are
f(-2) = 120, f(0) = 64 and f(1) = 84.
Step-by-step explanation: We are given the following function f(x) :
![f(x)=16x^2+4x+64~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)](https://tex.z-dn.net/?f=f%28x%29%3D16x%5E2%2B4x%2B64~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%28i%29)
We are to find the values of the following :
![(a)~f(-2),\\\\(b)~f(0),\\\\(c)~f(1).](https://tex.z-dn.net/?f=%28a%29~f%28-2%29%2C%5C%5C%5C%5C%28b%29~f%280%29%2C%5C%5C%5C%5C%28c%29~f%281%29.)
To find the values of the function at the given points, we need to substitute the corresponding values of x in equation (i).
Substituting x = -2 in equation (i), we get
![f(-2)=16\times(-2)^2+4\times(-2)+64=64-8+64=120.](https://tex.z-dn.net/?f=f%28-2%29%3D16%5Ctimes%28-2%29%5E2%2B4%5Ctimes%28-2%29%2B64%3D64-8%2B64%3D120.)
Substituting x = 0 in equation (i), we get
![f(0)=16\times0^2+4\times0+64=0+0+64=64.](https://tex.z-dn.net/?f=f%280%29%3D16%5Ctimes0%5E2%2B4%5Ctimes0%2B64%3D0%2B0%2B64%3D64.)
Substituting x = 1 in equation (i), we get
![f(1)=16\times1^2+4\times1+64=16+4+64=84.](https://tex.z-dn.net/?f=f%281%29%3D16%5Ctimes1%5E2%2B4%5Ctimes1%2B64%3D16%2B4%2B64%3D84.)
Thus, the required values are
f(-2) = 120, f(0) = 64 and f(1) = 84.
Answer:
30x8
8x0=0
8x3=24
30x8=240
Step-by-step explanation:
Answer: it’s at the middle
Step-by-step explanation: