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netineya [11]
2 years ago
13

F(x) = 7x + 1 - 8

Mathematics
2 answers:
notka56 [123]2 years ago
6 0

Answer: 7x-5

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)=(7x+1-8)-(-2)=\boxed{7x-5}

Allushta [10]2 years ago
6 0

Answer:

D. (f-g)(x) = |7x+1|-6

Step-by-step explanation:

f(x) = |7x + 1| - 8

g(x) = -2

(f - g)(x) = f(x) - g(x) = |7x + 1| - 8 - (-2)

(f-g)(x) = |7x + 1| - 6

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What is the multiplicative rate of change for the exponential function graphed to the left?
schepotkina [342]

Answer:

The multiplicative rate of change is 3

Step-by-step explanation:

The given graph passes through the points:

(-2,\frac{2}{9}),(-1,\frac{2}{3}),(0,2),(1,6),(2,18),(3,54)

The multiplicative rate of change is the factor that multiplies each y-value to give the subsequent y-values.

We can find that factor by dividing a y-value by the previous y-value of any two consecutive y-value.

The multiplicative rate of change is \frac{6}{2}=3 or \frac{18}{6}=3 or \frac{54}{18}=3  or \frac{2}{\frac{2}{3} } =3.

7 0
4 years ago
Use a translation rule to describe the translation of ABC that is 6 units to the right and 10 units down.​
vesna_86 [32]

Answer:

(x, y ) → (x + 6, y - 10 )

Step-by-step explanation:

6 units right is + 6 in the x- direction

10 units down is - 10 in the y- direction

the translation rule is

(x, y ) → (x + 6, y - 10 )

6 0
3 years ago
Whats the indicated operation?
Black_prince [1.1K]
4/11 * 10/8
= 1/11 * 10/2
= 1/11 * 5
= 5/11

answer 5/11
you got it correct
7 0
3 years ago
(4x-5)+2(3x+1)<br> Can you help me solve this plz for me
Korvikt [17]

Answer:

10x - 3

Step-by-step explanation:

First, distribute 2 to all terms within the second parenthesis:

2(3x + 1) = (2 * 3x) + (2 * 1) = 6x + 2

4x - 5 + 6x + 2

Combine like terms (terms with the same amount of variables).

4x + 6x + 2 - 5

(4x + 6x) + (2 - 5)

10x + (-3)

10x - 3

10x - 3 is your answer.

~

8 0
3 years ago
Read 2 more answers
Evaluate each expression. 3^-2
Rus_ich [418]
9 is the answer negatives cancel out creating positve
7 0
3 years ago
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