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Jobisdone [24]
3 years ago
5

Which is the equation of the line that passes through the point (-5, -2)

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

F) y=3x+13

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=3(x-(-5))

y+2=3(x+5)

y=3x+15-2

y=3x+13

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Find the ratio in which y-axis divides the line segment joining the points A(5, -6), and B (-1, -4). Also find the coordinates o
lora16 [44]

Answer:

Something like this

Step-by-step explanation:

distance √(-1 - 5)² + (-6 - -4)² = √36 + 4 = √40 = 6.32

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distance (-1,-4) to (0, -4.63)

√(-1 - 0)² + (-4 - -4.63...)² = √1.4 = 1.18

6.32 - 1.18 = 5.14

1.18 : 5.14

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3 years ago
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What is the value of x?<br> Enter your answer in the box.<br><br> x =
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Answer: x = 39  because 39 + 102 = 141 and 180 -  141 = 39

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3 years ago
Evaluate the spherical coordinate integral
expeople1 [14]

Rewrite the equations of the given boundary lines:

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<em>y</em> = 2<em>x</em> + 2  ==>  -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5  ==>  -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3

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The integral is then

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5 0
3 years ago
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Answer:

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