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2 years ago

How many

Mathematics

1 answer:

AVprozaik [17]2 years ago

6 0

Answer:the answer is

Step-by-step explanation:

First convert 7 1/2 to an improper fraction

15/2 ÷ 3/4

Division of fractions hold the first fraction replaces ÷ with x then flip the second fraction

15/2 x 4/3

Multiply the tops 15x4 =60

Over the bottoms multiplied together 2x3=6

60/6=10

10 people can be served that should help

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Multiply:<br>(x+y)by (x+y)<br>a+b by a^2-b^2<br>(a+5) by (a^2-2a-3)<br>(a^2-ab+b^3) by (a+b)

Law Incorporation [45]

Answer:

Multiply:

$(x+y)by (x+y)$

$: \implies(x + y)(x + y)$

$: \implies \: x(x + y) + y(x + y)$

$: \implies {x}^{2} + xy + xy + {y}^{2}$

$: \implies{x}^{2} + 2xy + {y}^{2}$

Multiply:

$a+b \: by \: a^2-b^2$

$: \implies( {a}^{2} + {b}^{2} ) \times (a + b)$

$: \implies \: {a}^{2} (a + b) - {b}^{2} (a + b)$

$: \implies \: {a}^{3} + {a}^{2} b - {ab}^{2} - {b}^{3}$

Multiply:

$(a+5) by (a^2-2a-3)$

$: \implies{(a + 5) \times ( {a}^{2} - 2a - 3) }$

$: \implies \: a({a}^{2} - 2a - 3) + 5( {a}^{2} - 2a - 3)$

$: \implies(a \times {a}^{2} - a \times 2a - a \times 3) + (5 \times {a}^{2} - 5 \times 2a - 5 \times 3)$

$: \implies{a}^{3} - {2a}^{2} - 3a + 5 {a}^{2} - 10a - 15$

$: \implies{ {a}^{3} + {3a}^{2} - 13a - 15}$

Multiply:

$(a^2-ab+b^3) by (a+b)$

$: \implies{(a + b) \times ( {a}^{2} - ab + {b}^{3} )}$

$: \implies \: a( {a}^{2} - ab + {b}^{3}) + b( {a}^{2} - ab + {b}^{3} )$

$: \implies {a}^{3} - {a}^{2} b + a {b}^{3} + {a^2b} - {ab}^{2} + {b}^{4}$

$: \implies{ {a}^{3}+ab^3 - ab^2+ {b}^{4} }$

Step-by-step explanation:

$\blue{ \frak{Seolle_{aph.rodite}}}$

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1 year ago

A company mailed out 896,988 coupon booklets. The company sent the same number of

Anuta_ua [19.1K]

Answer:

4 and 6

Step-by-step explanation:

10 and 8 leave a remainder so can't be equal number of booklet

7 0

1 year ago

Read 2 more answers

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

2 years ago

If h(x)= (f o g)(x) and h(x)= 4 √x+7, find g(x) if f(x) = 4 √x+1

stepladder [879]

(f o g)(x)=f(g(x))

so

h(x)=f(g(x))
$4\sqrt{x+7}=4\sqrt{g(x)+1}$
hmm, see the differences

x+7=g(x)+1

x+6=g(x)
g(x)=x+6

6 0

2 years ago

Which measurement is equivalent to 850 mg?

stepladder [879]

Answer:

0.00187393

Hope this helps! :)

Please mark me the Brainliest!

6 0

2 years ago