We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
Ok bet jdhdhrhhdhdhfhhfhfhfhhfhhfhdhdhjfhfhfhfhfhjfjfhhfhfhfhfhjfhfhjfhfjfjfbdvbdbdhdh gg fhhdhdhdhdhfhfhfhfhfhfhffhhfhfhfhfhfhfhfhhfhfhfhjfjfhfhfhfhfhhfhfhfhfhfhhfhfhfjghfjfhfjfhfjgjjgjgjgjgjgjjgjgjgjgjjgjgjgjgjgjhfhjfh
(x1,y1) = (-2,7)
m = -5
(x,y) = (a,2)
Forming the equation,
(y-y1) = m(x-x1)
y - 7 = -5[x - (-2)]
y - 7 = -5x - 10
y + 5x = -3
Putting the values of (x,y) we get,
2 + 5a = -3
5a = -5
a = -1
Answer:
sorry you can send me picture of work
Step-by-step explanation:
ok send me and get answers
A food web
It shows the flow of an energy iban ecosystem