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Furkat [3]
3 years ago
11

When y= 55, x= 1/4. What is the value of y when x is 2.5?

Mathematics
1 answer:
Sergio [31]3 years ago
6 0

Answer:

y = 550 when x = 2.5

Step-by-step explanation:

various ways to work this through: one simple way is to do cross method. arrange the numbers into fractions like this and then multiply the ones diagonal from each other

\frac{55}{0.25} =\frac{y}{2.5}

then multiply 55*2.5 together. multiply 0.25 and y together. Now you have this:

137.5 = 0.25y

solve for y and you get y = 550

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Four times the reciprocal of a number equal 2 times the reciprocal of 8
garik1379 [7]

Answer:

Step-by-step explanation:

Let the number be y & reciprocal simply means inverse of the number

4×1/y=2×1/8 solving for y

4/y=2/8; y = 16

5 0
3 years ago
In 4 month, 104 gallons were used(determine gallons per month)
saw5 [17]
All you have to do is divide 104 by 4! The awnser is 26
6 0
3 years ago
Service calls arriving at an electric company follow a Poisson distribution with an average arrival rate of 5656 per hour. Find
liberstina [14]

Answer:

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The variance is the same as the mean.

Average rate of 56 calls per hour:

This means that \mu = 56n, in which n is the number of hours.

Find the average and standard deviation of the number of service calls in a 15-minute period.

15 minute is one fourth of a hour, which means that n = \frac{1}{4}. So

\mu = 56n = \frac{56}{4} = 14

The variance is also 14, which means that the standard deviation is \sqrt{14} = 3.74

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

4 0
2 years ago
I am being asked to calculate and plot residuals and I don't know how my x values are 13.8, 18, 16,7, 18, 0.7, 21.9, 9.2, 19.5,
Igoryamba

Answer:

(13.8,1.42) (18,3.7)(16.7,3.21) and so on REMEMBER ITS (X,Y)

Step-by-step explanation:

3 0
3 years ago
What are the real solutions of x squared =225
Gnesinka [82]

The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.

<h3>What are the real solutions of the equation as given in the task content?</h3>

It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;

x² = 225

x = ± 15

Therefore, the real solutions of the equation are; +25 and -25.

Read more on real solutions of equations;

brainly.com/question/3122484

#SPJ1

3 0
2 years ago
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