F (x + 2) is a factor of x3 − 6x2 + kx + 10, k =

1 answer:

6 0

X+2 is a factor of given polynomial So x=-2 is a zero of that polynomial Now Put the value of x in polynomial X3-6x2+kx+10=0 (-2)^3-6×(-2)^2-k×2+10=0 Or -8-24-2k+10=0 Or -32+10=2k Or -22=2k So K=-11

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