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Charra [1.4K]
3 years ago
11

A 21-year-old female driver buys 25/50/50 liability insurance, collision insurance with a $500 deductible, and comprehensive ins

urance with a $250 deductible.
What is her total annual car insurance premium?


$715.00



$858.00



$1036.75



$1230.00

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

Answer:

Total annual car insurance premium = $715

Missing Chart:

The question is incomplete and misses the chart which signifies the cost for bodily injury, collison and comprehensive insurance.

I have attached the missing chart.

Step-by-step explanation:

Using the chart, we will look at the following on the chart:

a) Bodily injury 25/50  having premium of <em>$</em><u><em>220 </em></u>

50 Property damage with premium of <em>$</em><u><em>245</em></u>

b) Collision insurance with $500 deductible has cost of <em>$</em><u><em>148</em></u>

c) Comprehensive insurance with $250 deductible has cost of <em>$</em><u><em>102</em></u>

Adding all these values :

220 +245 +148 +102 = $715

Which is the total annual car insurance premium

icang [17]3 years ago
4 0

Answer:

858.00

Step-by-step explanation:

I took the test

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We want to find \vec F_4 such that the object needs is in equilibrium:

\vec F_1+\vec F_2+\vec F_3+\vec F_4=\vec0

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\vec F_1\cdot\vec F_2=F_1F_2\cos95^\circ=245\cos95^\circ

\vec F_3 is perpendicular to both \vec F_1 and \vec F_2, so \vec F_1\cdot\vec F_3=\vec F_2\cdot\vec F_3=0.

If we take the dot product of \vec F_1 with the sum of all four vectors, we get

\vec F_1\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\vec F_1\cdot\vec F_1+\vec F_1\cdot\vec F_2+\vec F_1\cdot\vec F_3+\vec F_1\cdot\vec F_4=0

{F_1}^2+\vec F_1\cdot\vec F_2+0+\vec F_1\cdot\vec F_4=0

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We can do the same thing with \vec F_2 and \vec F_3:

\vec F_2\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies\vec F_2\cdot\vec F_4=-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)

\vec F_3\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies\vec F_3\cdot\vec F_4=-{F_3}^2

Finally, if we do this with \vec F_4, we get

\vec F_4\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies{F_4}^2=-\left(\vec F_1\cdot\vec F_4+\vec F_2\cdot\vec F_4+\vec F_3\cdot\vec F_4\right)

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\implies F_4=\sqrt{{F_1}^2+{F_2}^2+{F_3}^2+2(\vec F_1\cdot\vec F_2)}

\implies\boxed{F_4\approx36.2\,\mathrm N}

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