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maks197457 [2]
3 years ago
7

What is 1.7 and 5.62 in expanded form ?

Mathematics
2 answers:
Juliette [100K]3 years ago
6 0

Answer:one and seven tenths and five and sixty two hundredths i belive


Step-by-step explanation:


Nikolay [14]3 years ago
4 0

Answer:

5.62 = (5 x 1) + (6/10) + (2/100) Five and sixty-two hundredths.

Step-by-step explanation:


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In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
Directions: Match the product and quotients estimates below with the correct expression on the left
prohojiy [21]

Answer:

Answer is in attached image.

Step-by-step explanation:

Given the expressions, for which we have to find the estimates as per the expressions on the left.

The given expressions are:

1) 35 \times 23

2) 132 \div 168

3) 17.3 \times 18.4

4) 999 \div 208

5) 998 \times 211

Here, we need to find the rounded off numbers.

35 can be rounded to 40 and 23 to 20.

Therefore, equivalent to 35 \times 23 is 40 \times 20

132 can be rounded to 130 and 168 to 170.

Therefore, equivalent to 132 \div 168 is 130 \div 170.

17.3 can be rounded to 17.0 and 18.4 to 18.0.

Therefore, equivalent to 17.3 \times 18.4 is 17.0 \times 18.0.

999 can be rounded to 1000 and 208 to 210.

Therefore, equivalent to 999 \div 208 is 1000 \div 210.

998 can be rounded to 1000 and 211 to 210.

Therefore, equivalent to 998 \times 211 is 1000 \times 210.

The solution can be found in the attached image as well.

8 0
3 years ago
Fill in the blank.<br>(x+a) (x+b) = (___) (___)​
Inga [223]

Answer:

(x+a) (x+b)=x(x+b)+a(x+b)=x²+bx+ax+ab=x²+x(a+b)+ab

7 0
3 years ago
Read 2 more answers
16. A negative number x a negative number is always positive. *<br> true<br> false<br> nositi
xenn [34]

Answer:

True.

Step-by-step explanation:

I don't know the explanation behind any of it, but a negative number, when multiples by another negative number, is always positive.

3 0
2 years ago
Here are the points that Noah scored in 7 basketball games last season
icang [17]

Answer:

7

Step-by-step explanation:

its the middle number between the first and last

hope this helps!

8 0
3 years ago
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