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3 years ago

Find the 21st term of the AP 1,3,5,7,

Mathematics

2 answers:

sweet [91]3 years ago

5 0

Answer:

are you Philippines ty points

madreJ [45]3 years ago

4 0

Answer:

a₂₁ = 41

Step-by-step explanation:

The nth term of an AP is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = a₂ - a₁ = 3 - 1 = 2 , then

a₂₁ = 1 + (20 × 2) = 1 + 40 = 41

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What is 10% of 17.01$

Gnesinka [82]

Answer:

1.701

Step-by-step explanation:

the word OF means to multiply

so in order to do this..

FIRST: make 10% into .10 because the % sign goes 2 times to the right

SECOND: you do .10 times 17.01

FINALLY: you get 1.701

8 0

3 years ago

Lena currently has a balance of -$10.48 in his checking account. Her bank requires her to maintain a minimum balance of $20. How

Goshia [24]

Answer

$30.48

Step-by-step explanation:

Find out how to get fro, -10.48 to 20. When you add .48 it makes it just $10. Add 30 more and get $20.

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3 years ago

Match each differential equation to a function which is a solution.

inessss [21]

Answer: 1 - C

2 - E

3 - no answer

4 - B

Step-by-step explanation:

A. $y = 3x+x^2$

$y' = 3 + 2x\\y'' = 2$

Replace in 1:

$y'' + y = 0$

$2 + 3x + x^2 \neq 0$

So, A is not an answer for 1

Replace in 2:

$y' = 3y$

$3+2x = 3(3x + x^2)$

So, A is not an answer for 2

Replace in 3

$2x^2y'' + 3xy'= y$

$2x^2(2) + 3x(3 + 2x) = 4x^2 + 9x + 6x^2 \neq 3x+x^2$

So, A is not an answer for 3

Replace in 4

$y'' + 6y' + 8y = 0$

$2 + 6(3+2x)+8(3x + x^2) = 2+18+12x+24x+8x^2 \neq 0$

So, A is not an answer for 4

B. $y = e^{-4x}$

$y' = -4e^{-4x}$

$y'' = 16e^{-4x}$

Replace in 1

$y'' + y = 0$

$16e^{-4x} -4e^{-4x} = 12e^{-4x} \neq 0$

So, B is not an answer for 1

Replace in 2

$y' = 3y$

$-4e^{-4x} \neq 3e^{-4x}$

So, B is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(16e^{-4x}) +3x(-4e^{-4x}) \neq e^{-4x}$

So, B is not an answer for 3

Replace in 4

$y'' + 6y' +8y = 0$

$16e^{-4x} + 6(-4e^{-4x}) + 8e^{-4x} = e^{-4x}(16-24+8) = 0$

So, B is an answer for 4

C. $y = sin(x)$

$y' = cos(x)$

$y'' = -sin(x)$

Replace in 1

$y'' + y = 0$

$-sin(x) + sin(x) = 0$

So, C is an answer for 1

We jump to

D. $y = x^{12}$

$y' = 12x^{11}$

$y'' = 132 x^{10}$

Replace in 2

$y' = 3y$

$12x^{11} \neq 3x^{12}$

So, D is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(132x^{10}) + 3x(12x^{11}) = 300x^{12} \neq x^{12}$

So, D is not an answer for 3

E. $y = 6e^{3x}$

$y' = 18e^{3x}$

$y'' = 54e^{3x}$

Replace in 2

$y' = 3y$

$18e^{3x} = 3(6e^{3x}) = 18e^{3x}$

So, E is an answer for 2

3 0

3 years ago

#1. Which of the following suffixes means “bearing or producing”? A. -osis B. -oferous C. -fic D. -oid....#2. Which of the follo

AlexFokin [52]

#1-fic
#2 -oid

I took latin suffixes

5 0

3 years ago

Imagine two lines intersect. How can the properties of linear pairs and vertical angles help to determine the angle measures cre

Art [367]

<span>Vertical angles are opposite angles that share only a vertex.
When two lines intersect, we have two sets of vertical angles.

Linear pairs are two angles that form a straight line; when two lines intersect, we have two linear pairs.

If we know one of the angles formed when two lines intersect, we know that the angle opposite it, the vertical angle, has the same measure.
We also know that the angle beside it, that forms a linear pair, will be supplementary with it (add to 180); this means we can find its measure by subtracting from 180.
The remaining missing angle will be the same as this supplementary angle, since they are vertical angles</span>

3 0

3 years ago

Read 2 more answers

Find the 21st term of the AP 1,3,5,7,​

Find the 21st term of the AP 1,3,5,7,