Sinα=h/L
α=arcsin(h/L)° we are told that h=18 and L=20 so
α=arcsin(9/10)°
α≈64° (to nearest whole degree)
Step-by-step explanation:
Length of rectangle is 140 m and its breadth is 100 m
Perimeter = sum of all sides
For rectangle, P = 2(l+b)
P = 2(140+100)
P = 480 m
Area = length × breadth
For a rectangle, A = lb
A = 140 × 100
A = 14000 m²
We need to write the length and breadth such that it has the same perimeter but a larger area.
Let the length is 110 m and breadth is 130 m.
Perimeter, P = 2(110+130)
P = 480 m
Perimeter is same as previous
Area, A = 110 × 130
A = 14300 m²
Area is more than the initial area.
Hence, this is the required solution.
Answer:
D=12/2
Step-by-step explanation:
Let's simplify step-by-step.
2−v18−
2
/12
+2v18
=2+−v18+
−1
/6
+2v18
(−v18+2v18)+(2+
−1
/6
)
v18+
11
/6
D=Correcto
2-V^{18}-2/12+2V^{18}=12/2
v=1.082512
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Answer:
x - intercept(s) : ( -9, 0 )
y - intercept(s) : ( 0, 54 )
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