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3 years ago

Use (r,16) to solve y=2x-4

1 answer:

4 0

(x,y) = (r,16)

With this knowledge, plug in r for x, and 16 for y

16 = 2(r) - 4

Isolate the r, add 4 to both sides

16 (+4) = 2r - 4 (+4)

20 = 2r

Divide 2 from both sides

20/2 = 2r/2

r = 20/2

r = 10

hope this helps

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What are the two possible answers for the equation Ix/5I = 3?

bagirrra123 [75]

Answer:

Either $x = -15$ or $x = 15$ .

Step-by-step explanation:

$|x| = \left\lbrace \begin{aligned} & x && \text{if $x \ge 0$} \\ & -x && \text{if $x < 0$}\end{aligned}\right.$ .

Hence, there are two possibilities to consider:

Either $(x / 5) \ge 0$ ,
Or $(x / 5) < 0$ .

If $(x / 5) \ge 0$ , then $|x / 5| = x / 5$ .

Substitute into the original equation: $x/ 5= 3$ . Solve for $x$ : $x = 15$ .

Important: verify that the solution $x = 15$ meet the assumption $(x / 5) \ge 0$ . Indeed, $(x / 5) = (15 / 5) = 3$ and is indeed non-negative. Hence, the solution $x = 15\!$ is valid.

On the other hand, if $(x / 5) < 0$ , then $|x / 5| = - x / 5$ .

Substitute into the original equation: $(-x / 5) = 3$ . Solve for $x$ : $x = -15$ .

Similarly, verify that the solution $x= - 15$ satisfies the current assumption that $(x / 5) < 0$ . Indeed, this assumption is met, and $x = -15$ is also a valid solution.

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2 years ago

Which equation has a constant proportional equal to 1/2

Sedaia [141]

Answer:

2/4 or 3/6

Step-by-step explanation:

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3 years ago

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for every 16 basketball players in crystal county schools there are 48 soccer players. if the ratio remains constant and there a

Dmitry_Shevchenko [17]

Answer:

16:48

64:192

Step-by-step explanation:

16:48

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64/16=4

48 x 4=192

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3 years ago

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Simplify. (5x^3y^2+x^2-6x^2y^3) - (3x^2y^3-4y^3+7x^2)

Zanzabum

Answer:

Step-by-step explanation:

The initial expression is:

$(5x^{3}y^{2}+x^{2}-6x^{2}y^{3})-(3x^{2}y^{3}-4y^{3}+7x^{2})$

Using BEMDAS (Brackets - Exponents - Multiplication - Division - Addition -Subtraction), we first start with brackets:

$5x^{3}y^{2}+x^{2}-6x^{2}y^{3}-3x^{2}y^{3}+4y^{3}-7x^{2}$

Remember that if there is a negative sign, it will change the signs of the terms within the brackets.

Then, collecting like terms:

$5x^{3}y^{2}-9x^{2}y^{3}+4y^{3}-6x^{2}$

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3 years ago

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m_a_m_a [10]

If (x^2 -10) is one of the factors, that can be further factored into:
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I then used an algebraic long division calculator
http://calculus-calculator.com/longdivision/
to calculate:
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</span>x^2 + 5x + 9

Using the quadratic formula, the roots of that equation are:
x = -5 + sqrt (-11) / 2
and
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Both of those roots are not real.

I tried using online graphing calculators for x^4+5x^3-x^2-50x-90=0 but none worked.

2. For this equation,
<span>3x^2 ‒ 8x + k = 0
I used my OWN quadratic formula calculator
http://www.1728.org/quadratc.htm
and found that real roots no longer exist after "k" is greater than 5.3

</span>

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3 years ago