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3 years ago

6

A definition of a statistical question is given below.

2 answers:

ZanzabumX [31]3 years ago

6 0

Answer:

I dont know

Step-by-step explanation:

tiny-mole [99]3 years ago

4 0

First 2 are statistical, because you are asking more than one person, which will result in more than one number(more than one data value)

The other questions are about one person asking one other person about something to get numerical data.
If you only ask 1 person, you will have 1 answer. 1 answer is one data value, but statistical questions must have more than one data value.

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in one year angelicas height went from 60 inches to 63 inches. What as the percent of increase in angelicas height?

SpyIntel [72]

5% total increase, as 3 to 60 is 1/20 (5%)

7 0

4 years ago

10.2 = 0.6y what is y

AVprozaik [17]

Answer:

y = 17

Step-by-step explanation:

isolate the variable by dividing each side by factors that don't contain the variable.

6 0

3 years ago

Please help me solve and explain these two questions:

Rama09 [41]

Answer:

go by basics u will get it easier

Step-by-step explanation:

assume X2 + e3x as some function t

now find derivative you get (1/t )dt/dx

now find dt /dx. simply derivative with respect to x

for second question use formula

dy/dx = - partial derivative of function with x / partial derivative of function with respect to y

5 0

3 years ago

The question on the bottom

TEA [102]

Answer:

9th grade student=33.3%, unit 7=45%

Step-by-step explanation:

5 0

3 years ago

If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .

ollegr [7]

Answer:

$2y^2-7y+6=0$

Step-by-step explanation:

We are given that $\alpha$ and $\beta$ are the zeroes of the polynomial $6y^2-7y+2$

$y^2-\frac{7}{6}y+\frac{1}{3}$

We have to find a quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ .

General quadratic equation

$x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes$

We get

$\alpha+\beta=\frac{7}{6}$

$\alpha \beta=\frac{1}{3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3$

Substitute the values

$y^2-(7/2)y+3=0$

$2y^2-7y+6=0$

Hence, the quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ is given by

$2y^2-7y+6=0$

4 0

4 years ago