Long ears have to be dominant:
If this IS true then these would be your 'parents':
L = long ears
l = curly ears
LL x ll
If you cross the homozygous recessive curly eared rabbit (ll) with homozygous dominant long eared rabbit (LL) you would get 100% Ll - all would look long eared.
Since we were given only one point, we have to test each exponential function for the point

Since exponential functions are of the form

, The correct option is between option A and option C.
For option A,

On substitution, we have;



.
Since the point satisfied the exponential function

, the exponential function goes through it.
Hence the correct answer is option A.
No need to test for option C again.
Answer:
Due to the fact that when crossing the isolated lines, the F1 progeny expression resulted in all alleles having blue shells and long antennas, the dominant <em>shell/color & length/antenna</em> combination is:
<em>"</em><em>Blue Shell & Long Antenna</em><em>"</em>
Answer: B. The endoplasmic reticulum
Explanation: GOOGLE
Answer:
The correct answer is- law of independent assortment
Explanation:
Law of independent assortment says that assortment of one gene pair is independent of assortment of other gene pair which means each contrasting gene pair bears no association with other pairs of contrasting character and behave and segregate independently.
This allows the combination of new characters in the offspring. So it helps in increasing the genetic variability in the gene pool. Therefore law of independent assortment tells that inheritance of one trait had no effect on the inheritance of another.