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3 years ago

Which compound inequality is equivalent to |ax-b|>c for all real numbers a, b, and c, where c>0

Mathematics

2 answers:

Doss [256]3 years ago

8 0

Answer:

Step-by-step explanation:

Keywords

compound inequality, absolute value, equivalent

we have

we know that

To find the compound inequality calculate the two solutions of the absolute value

First solution (case positive)

-------> inequality A

Second solution (case negative)

-------> inequality B

Multiply by all expression

therefore

is equivalent to

and

The answer is

The equivalent compound inequality is

garik1379 [7]3 years ago

6 0

Answer:

D. ax-b<-c or ax-b>c is the correct answer.

Step-by-step explanation:

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The goals against average (A) for a professional hockey goalie is determined using the formula A=60(g/2). In the formula, g repr

maks197457 [2]

Answer:

g = At/60

Step-by-step explanation:

Given:

A = 60(g/t)

60(g/2) is a mistake in the question which the question has corrected in the comments)

A is the average for a professional hockey goalie.

g is the number of goals scored against the goalie.

t represents the time played in minutes.

Finding 'g':

A = 60(g/t)

can be written as A = (60*g)/t

Multiplying by 't' on both sides:

At = (60*g)*t/t

At = 60*g

Dividing by '60' on both sides:

At/60 = 60*g/60

At/60 = g

⇒ g = At/60

3 0

3 years ago

Read 2 more answers

The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies No

Greeley [361]

Answer:

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.02 g/mi

Standard Deviation, σ = 0.01 g/mi

Sample size, n = 81

We are given that the distribution of level of nitrogen oxides is a bell shaped distribution that is a normal distribution.

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.01}{\sqrt{81}} = 0.0011$

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.01

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 0.02}{0.0011})=0.01$

$= 1 -P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.01$

$=P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.99$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 0.02}{0.0011} = -2.326\\\\x = 0.0174$

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

5 0

2 years ago

What is the average rate of change from x = -1 x = 2 equal to 5?

kherson [118]

Yes. And thanks.for free branana

7 0

2 years ago

The margin of error ________ (increases or decreases) with an increased sample size and ________ (increases or decreases) with a

rusak2 [61]

The margin of error decreases with an increased sample size and increases with an increase in confidence level.

5 0

2 years ago

Craig and Alissa are building a sandcastle on the beach. They each have a bucket. Craig's bucket holds 1/2 pound of sand and Ali

Nitella [24]

<h3>Amount of sand craig and Alissa collect together at one time is 1.4 pounds</h3>

<em><u>Solution:</u></em>

Given that,

Craig and Alissa are building a sandcastle on the beach. They each have a bucket

Craig's bucket holds 1/2 pound of sand and Alissa's bucket holds 9/10 pound of sand

Therefore,

$Craig\ bucket = \frac{1}{2}\ pound\\\\Alissa\ bucket = \frac{9}{10}\ pound$

<em><u>How much sand can craig Alissa collect together at one time</u></em>

Add both, we get

$Collect\ together = \frac{1}{2} + \frac{9}{10}\\\\Collect\ together = \frac{1 \times 5}{2 \times 5} + \frac{9}{10}\\\\Collect\ together = \frac{5}{10} + \frac{9}{10}\\\\Collect\ together = \frac{9+5}{10}\\\\Collect\ together = \frac{14}{10} = \frac{7}{5} = 1.4\\\\In\ mixed\ fractions,\\\\Collect\ together = 1\frac{2}{5}$

Thus, amount of sand craig and Alissa collect together at one time is 1.4 pounds

4 0

3 years ago