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Brrunno [24]
3 years ago
10

Which compound inequality is equivalent to |ax-b|>c for all real numbers a, b, and c, where c>0

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Keywords

compound inequality, absolute value, equivalent

we have

we know that

To find the compound inequality  calculate the two solutions of the absolute value

First solution (case positive)

-------> inequality A

Second solution (case negative)

-------> inequality B

Multiply by  all expression

therefore

is equivalent to

and  

The answer is

The equivalent compound inequality is

garik1379 [7]3 years ago
6 0

Answer:

D. ax-b<-c or ax-b>c is the correct answer.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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jekas [21]

Answer:

Incomplete question, but you can use the formulas given to solve it.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

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7 0
3 years ago
How do I solve #14????
Tcecarenko [31]
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I hope this helps!
~kaikers
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Answer:

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Step-by-step explanation:

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