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3 years ago

Explain the bonding between molecules in DNA.

Biology

1 answer:

Artist 52 [7]3 years ago

4 0

Answer: The DNA double helix is held together by two types of bonds,

covalent and hydrogen.

Explanation: Covalent bonds occur within each linear strand and strongly

bonds the bases, sugar and phosphate groups.

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What the current produced by the X-ray tube during an exposure called?

Sauron [17]

Answer:

dear user

the current produced by the x ray tube during an exposure is called anode or tube current

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4 years ago

Describes the structure of nucleic acids

dem82 [27]

The secondary structure is responsible for the shape that the nucleic acid assumes. The bases in the DNA are classified as purines and pyrimidines. ... A purine base always pairs with a pyrimidine base (guanine (G) pairs with cytosine (C) and adenine (A) pairs with thymine (T) or uracil (U)).

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4 years ago

Cardiovascular disease and ________ account for approximately 29% of U.S. a. deaths each year. b. stroke lung cancer c. leukemia

emmasim [6.3K]

Answer: diabetes mellitus

Explanation:

This is a disease condition associated with elevated blood glucose levels.

It is due to abnormalities of the Pancreas. The pancreas coordinates two hormones INSULIN AND GLUCAGON in its cells.

INSULIN converts excess sugar to GLYCOGEN while GLUCAGON breaks down GLYCOGEN to sugar when blood glucose/glucose levels drops.

If the pancreas beta-cells of glucose are faulty, INSULIN fails to converts excess glucose to glycogen; therefore glucose builds up in the blood plasma,and failed to enter the needed cells. Large amount of glucose is wasted in urine.This is diabetes Mellitus.

The two types of diabetes are:

Type 1 and Type 2.

3 0

3 years ago

Need answer quick please thanks

Lady bird [3.3K]

Answer:

The genotype will be: Bb

4 0

3 years ago

Read 2 more answers

Since the llamas will not sell well with malformed feet, you decide to select the herd against this defect. You separate the aff

swat32

The question is incomplete as the frequency of alleles is not given, however, the frequency and population are given below :

Frequency of a = 0.506

total population = 500, Number of aa = 128

Answer:

The correct answer is - option C. 0.336.

Explanation:

Let, A = Normal allele, a = Defective allele

So, AA & Aa will develop normal phenotype & aa will develop defective phenotype.

Frequency of a = 0.506

So, Frequency of A = 1 - 0.506 = 0.494

So, frequency of AA = (0.494)2 = 0.244036

So, frequency of Aa = 2 x 0.494 x 0.506 = 0.499928

so, frequency of aa = (0.506)2 = 0.256036

total population = 500, Number of aa = 128

So, Number of AA = (0.494)2 x 500

= 122.018 which is almost 122 so considering it 122

So, Number of Aa = (2 x 0.494 x 0.506) x 500

= 249.964 which is almost 250 so considering it 250

It is given that, Relative fitness of AA (W11) & Aa (W12) is 1, and the relative fitness of aa (W22) is 0.

Now, mean fitness = (Frequency of AA x Fitness of AA) + (Frequency of Aa x Fitness of Aa) + (Frequency of aa x Fitness of aa)

= (0.244036 x 1) + (0.499928 x 1) + (0.256036 x 0) = 0.244036 + 0.499928 = 0.743964

So, after selection frequency of Aa

= (Frequency of Aa x Fitness of Aa) / mean fitness

= 0.499928 / 0.743964 = 0.67198 (Up to 5 decimal)

So, after the selection frequency of aa

= (Frequency of aa x Fitness of aa) / mean fitness

= 0 / 0.743964 = 0

So, frequency of a

= 1/2 of frequency of Aa + Frequency of aa

= 1/2 x 0.67198 + 0

= 0.33599 + 0

= 0.33599 which is almost 0.336

8 0

3 years ago