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3 years ago

Find f'(x) for f(x) = cos^2(3x^3).

1 answer:

6 0

$f(x) = \cos^2(3x^3)\\f'(x) = \frac{d}{dx}[\cos^2(3x^3)]\\= 2\cos(3x^3) \cdot \frac{d}{dx}[cos(3x^3)]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot \frac{d}{dx}[3x^3]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot 9x^2\\= -18x^2\cos(3x^3)\sin(3x^3)$

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Please show your work!!!!

viva [34]

Answer:

4√34

Step-by-step explanation:

Let the unknown side be y

y^2 = 20^2 + 12^2

y^2 = 400 + 144

y^2 = 544

Take the square root of both side

y = √544

y = √(16x34)

y = √16 x √34

y = 4√34

6 0

3 years ago

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andreyandreev [35.5K]

Answer:

Q1.

a. three hundred sixty-four thousand eight hundred twenty-five

b. one hundred forty-three

c. nine hundred four thousand three hundred six

d. seven million twenty

e. fifty-six million thirty thousand one hundred twenty-three

f. six thousand twenty-four

g. two hundred four

h. six hundred seventy-four thousand one

i. nine hundred sixty-two thousand three hundred forty-two

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a. 5000000

b. 1000004

c. 60000203

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e. 286

f. 34503271

g. 844536

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j. 4605231

5 0

3 years ago

Part 1: Use the information provided to write the standard form equation of each circle. Please show the work.

dusya [7]

Answer:

1. (x + 2)² + (y - 9)² = 64

2. (x + 6)² + (y - 9/2)² = 100

3. (x - 15)² + (y + 10)² = 1

Step-by-step explanation:

Equation of a circle:

(x - h)² + (y - k)² = r²

1. Center: (-2, 9), Radius: 8

(x - (-2))² + (y - 9)² = 8²

(x + 2)² + (y - 9)² = 64

2. Center: (-6, 9/2), Radius: 10

(x - (-6))² + (y - (9/2))² = 10²

(x + 6)² + (y - 9/2)² = 100

3. Center: (15, -10), Radius: 1

(x - 15)² + (y - (-10))² = 1²

(x - 15)² + (y + 10)² = 1

4 0

3 years ago

Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript

PIT_PIT [208]

Answer:

$f(x)=4\sqrt[3]{16}^{2x}$

Step-by-step explanation:

We believe you're wanting to find a function with an equivalent base of ...

$4\sqrt[3]{4}\approx 6.3496$

The functions you're looking at seem to be ...

$f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x$

The third choice seems to be the one you're looking for.

9 0

3 years ago

Read 2 more answers

A local gym charges a $100 initial membership fee and $19 for each month you stay a member. What are the x and y intercepts?

guapka [62]

Answer:

y-intercept = 100
x- intercept = -5.26

Step-by-step explanation:

$100 initial membership fee
$19 monthly fee

Function of relationship:

y = 19x + 100

y- intercept:

x =0 ⇒ y = 19*0 + 100 ⇒ y = 100

x - intercept:

y = 0 ⇒ 0 = 19x + 100 ⇒ 19x = -100 ⇒ x = -100/19 ⇒ x = -5.26

5 0

3 years ago