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3 years ago

What is the simplest form of 15 75

Mathematics

1 answer:

vladimir1956 [14]3 years ago

8 0

Answer:

If you mean 15 over 75 (15/75), it will be 1/5

Step-by-step explanation:

15/75 can be divided my 15 on both numbers

15/15=1 and 75/15 will be 5

So, the simplest form is 1/5

You might be interested in

What is the solution of the inequality 9 - x^2<0?

Dmitry_Shevchenko [17]

Answer:

$x < -3\quad \mathrm{or}\quad \:x > 3$

Step-by-step explanation:

Given:

$9-x^2 < \:0$

Solve:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}$

$9-x^2-9 < 0-9$

$\mathrm{Simplify}$

$-x^2 < -9$

$Multiply\:both\:sides\:by\:-1\:$

$\left(-x^2\right)\left(-1\right) > \left(-9\right)\left(-1\right)$

$\mathrm{Simplify}$

$x^2 > 9$

$\mathrm{For\:}u^n\: > \:a\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\: < \:-\sqrt[n]{a}\:or\:u\: > \:\sqrt[n]{a}$

$x < -\sqrt{9}\quad \mathrm{or}\quad \:x > \sqrt{9}$

$\sqrt{9}=3$

$x < -3\quad \mathrm{or}\quad \:x > 3$

~lenvy~

5 0

2 years ago

4.12 x 2.1= can i get answer and work please

alexdok [17]

Answer:

8.652

Step-by-step explanation:

Ignore the points and multiply, then you see that 4.12 has two decimal places and that 2.1 has one decimal place, when you add them there is three decimal places.

412 x 21 = 8652

4.12 x 2.1 = 8.652

Pls mark me as brainliest!!!!

3 0

3 years ago

Read 2 more answers

The diameters of bearings used in an aircraft landing gear assembly have a standard deviation of ???? = 0.0020 cm. A random samp

vovikov84 [41]

Answer:

(a) We conclude after testing that mean diameter is 8.2500 cm.

(b) P-value of test = 2 x 0.0005% = 1 x $10^{-5}$ .

(c) 95% confidence interval on the mean diameter = [8.2525 , 8.2545]

Step-by-step explanation:

We are given with the population standard deviation, $\sigma$ = 0.0020 cm

Sample Mean, Xbar = 8.2535 cm and Sample size, n = 15

(a) Let Null Hypothesis, $H_0$ : Mean Diameter, $\mu$ = 8.2500 cm

Alternate Hypothesis, $H_1$ : Mean Diameter, $\mu$ $\neq$ 8.2500 cm{Given two sided}

So, Test Statistics for testing this hypothesis is given by;

$\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ follows Standard Normal distribution

After putting each value, Test Statistics = $\frac{8.2535-8.2500}{\frac{0.0020}{\sqrt{15} } }$ = 6.778

Now we are given with the level of significance of 5% and at this level of significance our z score has a value of 1.96 as it is two sided alternative.

Since our test statistics does not lie in the rejection region{value smaller than 1.96} as 6.778>1.96 so we have sufficient evidence to accept null hypothesis and conclude that the mean diameter is 8.2500 cm.

(b) P-value is the exact % where test statistics lie.

For calculating P-value , our test statistics has a value of 6.778

So, P(Z > 6.778) = Since in the Z table the highest value for test statistics is given as 4.4172 and our test statistics has value higher than this so we conclude that P - value is smaller than 2 x 0.0005% { Here 2 is multiplied with the % value of 4.4172 because of two sided alternative hypothesis}

Hence P-value of test = 2 x 0.0005% = 1 x $10^{-5}$ .

Probability(-1.96 < N(0,1) < 1.96) = 0.95 { This indicates that at 5% level of significance our Z score will lie between area of -1.96 to 1.96.

P(-1.96 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96\frac{\sigma}{\sqrt{n} }$ < $Xbar - \mu$ < $1.96\frac{\sigma}{\sqrt{n} }$ ) = 0.95