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stellarik [79]
3 years ago
6

Today Ian wants to run less than 7/12 mile which of the following distances is less than 7/12?

Mathematics
2 answers:
Viefleur [7K]3 years ago
8 0
X=1 or x=2 because math is math
dybincka [34]3 years ago
6 0

A fraction with a denominator of 4 that is less than 7/12 miles is 1/4.Let the fraction be  x/4. Since this fraction must be less than 7/12 miles, we can write the inequality,  x/4 < 7/12.We now solve the inequality for x to obtain,  x<7/12(4).

This simplifies to x<7/3

This implies that x<2 1/3

This is distance so x is positive.

So we can choose x=1 or x=2.

Therefore the possible fractions include 1/4 or 2/4.

In the simplest form, the most appropriate fraction is 1/4





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Write a fraction, a decimal, and a percent that sum to 1 or 100%.
NemiM [27]

Answer:

Fraction: 1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10 etc.

Decimal: 1.00

Percent: 100%

3 0
3 years ago
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A plumbers bill is £463.20 plus VAT. The current rat of VAT is 20%. What is the actual cost of work done?
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£555.84

1% of the original value ×20 is £92.64. Add that to the original value (£463.20)
8 0
3 years ago
(a) The plane y + z = 13 intersects the cylinder x2 + y2 = 25 in an ellipse. Find parametric equations for the tangent line to t
klemol [59]

Answer:

Step-by-step explanation:

We have a curve (an ellipse) written as the system of equations

\begin{cases} y+z &= 13\\ x^2+y^2 &= 25\end{cases}.

And we want to calculate the tangent at the point (3,4,9).

The idea in this problem is to consider two variables as functions of the third. Usually we consider y and z as functions of x. Recall that a curve in the space can be written in parametric form in terms of only one variable. In this case we are considering the ‘‘natural’’ parametrization (x, y(x), z(x)).

Recall that the parametric equation of a line has the form

r(t)=\begin{cases} x(t) &= x_0 + v_1t \\ y(t) &= y_0 +v_2t\\ z(t) &= z_0 +v_3t \end{cases},

where (x_0,y_0,z_0) is a point on the line (in this particular case is (3,4,9)) and (v_1,v_2,v_3) is the direction vector of the line. In this case, the direction vector of the line is the tangent vector of the ellipse at the point (3,4,9).

Now, if we have the parametric equation of a curve (x, y(x), z(x)) its tangent line will have direction vector (1, y'(x), z'(x)). So, as we need to calculate the equation of the tangent line at the point (3,4,9) = (3, y(3), z(3)), we must obtain the tangent vector (1, y'(3), z'(3)). This part can be done taking implicit derivatives in the systems that defines the ellipse.

So, let us write the system as

\begin{cases} y(x)+z(x) &= 13\\ x^2+y^2(x) &= 25\end{cases}.

Then, taking implicit derivatives:

\begin{cases} y'(x)+z'(x) &= 0 \\ 2x+2y(x)y'(x) &= 0\end{cases}.

Now we substitute the values x=3 and y(3)=4, and we get the system of linear equations

\begin{cases} y'(3)+z'(3) &= 0 \\ 2\cdot 3+2\cdot 4y'(x) &= 0\end{cases},

where the unknowns are y'(3) and z'(3).

The system is

\begin{cases} y'(3)+z'(3) &= 0 \\ 6+8y'(x) &= 0\end{cases},

and its solutions are

y'(3) = -\frac{3}{4} and z'(3) = \frac{3}{4}.

Then, the direction vector of the tangent is

(1, -\frac{3}{4}, -\frac{3}{4}).

Finally, the tangent line has parametric equation

r(t)=\begin{cases} x(t) &= 3 + t \\ y(t) &= 4 -\frac{3}{4}t\\ z(t) &= 9 +\frac{3}{4}t \end{cases}

where t\in\mathbb{R}.

7 0
4 years ago
4+ x -17 =22 what's the awnser smart kids
Bingel [31]
Remember, you can do anything to an equation as long as you do it to both sides
4+x-17=22
add like terms
x+4-17=22
x-13=22
add 13 to both sides
x+13-13=22+13
x+0=35
x=35
6 0
3 years ago
Read 2 more answers
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