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3 years ago

Today Ian wants to run less than 7/12 mile which of the following distances is less than 7/12?

Mathematics

2 answers:

Viefleur [7K]3 years ago

8 0

X=1 or x=2 because math is math

dybincka [34]3 years ago

6 0

A fraction with a denominator of 4 that is less than 7/12 miles is 1/4.Let the fraction be x/4. Since this fraction must be less than 7/12 miles, we can write the inequality, x/4 < 7/12.We now solve the inequality for x to obtain, x<7/12(4).

This simplifies to x<7/3

This implies that x<2 1/3

This is distance so x is positive.

So we can choose x=1 or x=2.

Therefore the possible fractions include 1/4 or 2/4.

In the simplest form, the most appropriate fraction is 1/4

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3 years ago

f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many

Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Assuming that the proportion is estimated $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849$

And rounded up we have that n=1849

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3 years ago

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Verizon [17]

Answer:

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3 years ago

Determine the term life insurance amount per thousand on a 22-year-old female for a 5-year policy given that the face value of t

VLD [36.1K]

We need to determine the term life insurance amount per thousand on a 22-year-old female for a 5-year policy given that the face value of the policy is $600,000 and the annual premium is $1332.

Since we are supposed to find the term life insurance amount per thousand, therefore, we will use the following formula:

$\text{Term life insurance amount}=\frac{\text{Annual premium}}{\text{Face value of insurance}}*1000$

Upon substituting the values of annual premium and face value of insurance, we get:

$\text{Term life insurance amount}=\frac{\text{1332}}{\text{600000}}*1000\\
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Therefore, the required life insurance amount is $2.22.

4 0

3 years ago

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