5(x + 8) + x + y; x=3 and y=30

2 answers:

6 0

Plug in 3 for x and 30 for y

5(3 + 8) + 3 + 30

Use PEMDAS

5(11) + 3 + 30

55 + 33

88

88 is your answer

hope this helps

emmainna [20.7K]3 years ago

4 0

Substitute the variable's values for the variables themselves.

5(x + 8) + x + y =>
5(3 + 8) + 3 + 30

Use the order of operations to simplify this expression.

5(3 + 8) + 3 + 30
5(11) + 3 + 30
55 + 3 + 30
58 + 30
88

So, the answer is 88.

You might be interested in

Jada surveyed some students to see which tool they most favored for communicating with grit. The results of her survey are shown

nikklg [1K]

Answer:

120 students did Jada survey

Step-by-step explanation:

* Lets explain how to solve the problem

- The results of Jada survey are shown in this circle graph

# Communication tools Text messages 5/12

# Phone 1/5

# Emails 1/20

# Other messaging apps 1/3

- A total of 50 students said they favored text messages to

communicate with friends

- We need to find the total number of the students in Jada survey

- Assume that the total number of the students in the survey is x

∵ The Communication tools Text messages expressed by a

fraction 5/12 of the circle graph

∵ The total of 50 students said they favored text messages to

communicate with friends

- That means The fraction $\frac{5}{12}$ of x equivalent to 50

∴ $\frac{5}{12}*x=50$

- Multiply both sides by 12

∴ 5x = 600

- Divide both sides by 5

∴ x = 120

∵ x represents the number of the students in Jada survey

∴ 120 students did Jada survey

6 0

3 years ago

What is the value of the expression 2 + 32 ⋅ (5 − 1)?

cestrela7 [59]

Answer:

2+32 x (5-1) = 2 +32 x 4 = 2 + 128 = 130

Answer is 130

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$