Answer:
1/8 or 0.125
Step-by-step explanation:
Let x be the length of the sides of the square ABCD.
Therefore, the length of CN and CM is x/2.
The area of the triangle MCN is:
The area of the square ABCD is:
Thus, the probability that a random point lies in the triangle MCN is:
The probability that the point will lie in the triangle MCN is 1/8 or 0.125.
The equation is asking how much out of Jada's total budget (1545) is spent on electricity a month (47.20).
write this as a fraction 47.20/1545
type into calculator and you get .03055
multiply that by 100 to get it as a percent. you get 3.055%
now round that to the nearest tenth and you get 3.1%
answer 3.1%
Answer:
1
Step-by-step explanation:
By order of operations, we first evaluate the parentheses, which is 2 * 1 = 2. We then evaluate the brackets, which are 3 / 2 = 
. Finally, * 
= 
or 1.
We have
Plug in
:
⇒
So we now have
Plug in
:
⇒
⇒
![b=\sqrt[3]{\frac{95}{4}}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D)
which is approximately 2.874
So we get
![y=4(\sqrt[3]{\frac{95}{4}})^{x}](https://tex.z-dn.net/?f=y%3D4%28%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D%29%5E%7Bx%7D)
or, in decimal form,
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
