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nikklg [1K]
3 years ago
10

Graph the equations to solve the system. y = x + 4 y = -x - 6 choose the correct answer a.) solutions: all numbers on the line

Mathematics
1 answer:
Contact [7]3 years ago
8 0
Y = x + 4
y = -x - 6

x + 4 = -x - 6
x + x = -6 - 4
2x = -10
x = -10/2
x = -5

y = x + 4
y = -5 + 4
y = -1

one solution : (-5,-1)
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Step-by-step explanation:

5(-2)+30 = (-10)+30 = 20

6 0
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Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

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2 years ago
3(x-7) = 2 (x - 12) <br> i need help fast
gulaghasi [49]

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Step-by-step explanation:

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yanalaym [24]

Answer:

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Step-by-step explanation:

(6x^2 - 3 - 5x^3) - (4x^3 +2x^2 - 8)

distribute the minus sign

(6x^2 - 3 - 5x^3) - 4x^3 -2x^2 + 8

Combine like terms

-5x^3 -4x^3 +6x^2 - 2x^2 -3 +8

-9x^3+4x^2+5

6 0
3 years ago
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